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Which of the following accesses a variable in structure *b?
- a)b->var;
- b)b.var;
- c)b-var;
- d)b>var;
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Which of the following accesses a variable in structure *b?a)b->var...
None of the options provided access a variable in structure *b.
To access a variable in structure *b, we would need to dereference the pointer using the asterisk (*) operator. Additionally, we can use the dot (.) operator to access the variable within the structure.
The correct syntax would be:
(*b).variable
This can also be written using the arrow (->) operator as a shorthand:
b->variable
To access a variable in structure *b, we would need to dereference the pointer using the asterisk (*) operator. Additionally, we can use the dot (.) operator to access the variable within the structure.
The correct syntax would be:
(*b).variable
This can also be written using the arrow (->) operator as a shorthand:
b->variable
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Which of the following accesses a variable in structure *b?a)b->var...
Because arrow operator(->) is used to access members of structure pointer whereas dot operator(.) is used to access normal structure variables.
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