What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int a = 9;
int & aref = a;
a++;
cout << "The value of a is " << aref;
return 0;
}

Question

What will be the output of the following C++ code?

#include <iostream>
using namespace std;
int main()
{
int a = 9;
int & aref = a;
a++;
cout << "The value of a is " << aref;
return 0;
}

a)
9
b)
10
c)
error
d)
11

Correct answer is option 'B'. Can you explain this answer?

Answer

The value is declared and it isincrementedrement, so it’s value is 10.
$ g++ ref1.cpp
$ a.out
10

Answer

Explanation:

Reference Variable:
- In the given code, a reference variable `aref` is created which is referring to the variable `a`.
- The reference variable `aref` is essentially an alias for the variable `a`.

Incrementing the Value:
- The value of the variable `a` is incremented by 1 using the `a++` statement.
- After incrementing, the value of `a` becomes 10.

Output:
- When we print the value of `aref`, it will display the updated value of `a`, which is 10.
- Therefore, the output of the code will be 'The value of a is 10'.
Therefore, the correct answer is option 'B'.

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