A alone can do a piece of work in 6 days and B alone in 8 days. A and ...
Given:
A can do a piece of work in 6 days.
B can do a piece of work in 8 days.
A and B together completed the work for Rs.3200.
With the help of C, they completed the work in 3 days.
To find:
How much is to be paid to C?
Solution:
Let the total work be 48 units, which is the LCM of 6 and 8.
So, A can do 8 units of work in a day, and B can do 6 units of work in a day.
In 3 days, A completes 24 units of work, and B completes 18 units of work.
So, total work completed in 3 days = 42 units (24 + 18)
Remaining work = 6 units (48 - 42)
Let C can do x units of work in a day.
So, in 3 days, C completes 3x units of work.
Total work completed by A, B, and C in 3 days = 24 + 18 + 3x = 42 + 3x
As per the given condition, A, B, and C together completed the work for Rs.3200.
So, 1 unit of work is done for Rs.3200/48 = Rs.66.67
Therefore, 6 units of remaining work is done for Rs.66.67 x 6 = Rs.400.
Hence, the amount to be paid to C is Rs.400.
Therefore, option B is the correct answer.
A alone can do a piece of work in 6 days and B alone in 8 days. A and ...
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Work done by A in one day = 1/6.
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Work done by B in one day = 1/8
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Work done by C in one day = 1/3 - (1/6+1/8) = 1/3 -7/24 = (8-7)/24 = 1/24.
A's wage : B's wage : C's wage = 1/6 : 1/8 : 1/24 = 4: 3: 1
Therefore, C's share = (1/8) * 3200 = Rs 400.