A mixture of 150 liters of wine and water contains 20% water. How much...
Given:
Initial mixture contains 20% water
Volume of the mixture = 150 liters
To find:
Amount of water to be added to make the water 25% of the new mixture
Solution:
Step 1: Let's assume that x liters of water is added to the mixture.
Step 2: After adding x liters of water, the new volume of the mixture will be 150 + x liters.
Step 3: As per the question, the new mixture should contain 25% water.
Step 4: Therefore, the amount of water in the new mixture should be:
25% of (150 + x) = 0.25(150 + x)
Step 5: We know that initially, the mixture contained 20% water. Therefore, the amount of water in the initial mixture was:
20% of 150 = 0.20(150) = 30 liters
Step 6: In the new mixture, the amount of water will be 30 + x liters.
Step 7: Now, we can set up an equation to solve for x:
30 + x = 0.25(150 + x)
Step 8: Solving for x, we get:
x = 10
Therefore, 10 liters of water should be added to the mixture to make water 25% of the new mixture.
Hence, the correct answer is option (a) 10 liters.
A mixture of 150 liters of wine and water contains 20% water. How much...
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters. P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P
⇒ P = 10 liters.