Class 7 Exam > Class 7 Questions > Which of the following is illegal?a)int *ip;b...
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Which of the following is illegal?
- a)int *ip;
- b)string s, *sp = 0;
- c)int i; double* dp = &i;
- d)int *pi = 0;
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Which of the following is illegal?a)int *ip;b)string s, *sp = 0;c)int ...
Understanding the Options
When analyzing the legality of the given code snippets, it's essential to understand the data types and how pointers work in C/C++.
Option A: int *ip;
- This declares a pointer to an integer, which is perfectly legal.
Option B: string s, *sp = 0;
- This declares a string and a pointer to a string initialized to null. This is also legal.
Option C: int i; double* dp = &i;
- This option is illegal. Here’s why:
- `int i;` declares an integer variable.
- `double* dp = &i;` attempts to assign the address of an integer variable to a pointer meant for doubles. This is a type mismatch since an integer cannot be treated as a double.
Option D: int *pi = 0;
- This declares a pointer to an integer initialized to null. This is legal and commonly done to indicate that the pointer is not currently pointing to any valid memory.
Conclusion
In summary, option C is illegal due to the type mismatch between the integer variable and the double pointer. Pointers must match the type of the data they point to, making this assignment invalid. Understanding these fundamentals is crucial for working with pointers in C/C++.
When analyzing the legality of the given code snippets, it's essential to understand the data types and how pointers work in C/C++.
Option A: int *ip;
- This declares a pointer to an integer, which is perfectly legal.
Option B: string s, *sp = 0;
- This declares a string and a pointer to a string initialized to null. This is also legal.
Option C: int i; double* dp = &i;
- This option is illegal. Here’s why:
- `int i;` declares an integer variable.
- `double* dp = &i;` attempts to assign the address of an integer variable to a pointer meant for doubles. This is a type mismatch since an integer cannot be treated as a double.
Option D: int *pi = 0;
- This declares a pointer to an integer initialized to null. This is legal and commonly done to indicate that the pointer is not currently pointing to any valid memory.
Conclusion
In summary, option C is illegal due to the type mismatch between the integer variable and the double pointer. Pointers must match the type of the data they point to, making this assignment invalid. Understanding these fundamentals is crucial for working with pointers in C/C++.
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Which of the following is illegal?a)int *ip;b)string s, *sp = 0;c)int ...
dp is initialized int value of i.
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