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In a class, 40% of students passed English, 30% passed French and 10% passed both. If a student is selected at random, what is the probability that he has fail in both English and French?
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In a class, 40% of students passed English, 30% passed French and 10% ...
**Calculation of Probability of Failing in Both English and French**
**Given Information:**
- 40% of students passed English
- 30% of students passed French
- 10% of students passed both English and French
**Calculation:**
1. **Total Probability of Passing English:** 40%
2. **Total Probability of Passing French:** 30%
3. **Probability of Passing Both English and French:** 10%
**Formula:**
- Probability of failing in both English and French = Total Probability - Probability of Passing English - Probability of Passing French + Probability of Passing Both
**Calculation:**
- Probability of failing in both English and French = 100% - 40% - 30% + 10% = 40%
Therefore, the probability that a randomly selected student has failed in both English and French is 40%.
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In a class, 40% of students passed English, 30% passed French and 10% passed both. If a student is selected at random, what is the probability that he has fail in both English and French?
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