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Ashok cycles from his home to his school which starts at 8 a.m. If he cycles at 6 km/hr , he would reach the school 10 minutes late. If he cycles at 8 km/hr, he would reach the school 5 min early. At what speed should he cycle to reach school at 8 a.m. ?
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Most Upvoted Answer
Ashok cycles from his home to his school which starts at 8 a.m. If he ...
X/6-x/8=10/60-(-5)/602x/48=15/60x=48/8=6kmt at 6kmpht= 60minrequired time 50 min=5/6 hrthen speed = 36/5 kmph
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Ashok cycles from his home to his school which starts at 8 a.m. If he ...
Ashok's Cycling Speed to Reach School at 8 a.m.

To find the speed at which Ashok should cycle in order to reach school at 8 a.m., we need to analyze the given information.

Given:
- Ashok's school starts at 8 a.m.
- When Ashok cycles at 6 km/hr, he reaches the school 10 minutes late.
- When Ashok cycles at 8 km/hr, he reaches the school 5 minutes early.

Approach:
We can solve this problem by setting up two equations based on the given information and then solving them simultaneously.

Equation 1:
Let's assume the distance between Ashok's home and school is 'd' km.
When Ashok cycles at 6 km/hr, he reaches the school 10 minutes late, which means he takes 10 minutes more than the required time.
The time taken to reach the school at this speed can be calculated using the formula: Time = Distance / Speed.
So, the equation is:
d / 6 = (8 a.m. + 10 minutes) - 8 a.m.

Equation 2:
Similarly, when Ashok cycles at 8 km/hr, he reaches the school 5 minutes early, which means he takes 5 minutes less than the required time.
The equation is:
d / 8 = 8 a.m. - (8 a.m. - 5 minutes)

Solving the Equations:
Let's solve the above two equations simultaneously to find the value of 'd' (distance) and the required speed.

From Equation 1:
d / 6 = 10 minutes = 10/60 hours (since 1 hour = 60 minutes)

From Equation 2:
d / 8 = 5 minutes = 5/60 hours

Simplifying the equations:
d = 6 * 10/60 = 1 km
d = 8 * 5/60 = 2/3 km

Since both the distances are equal, we have:
1 km = 2/3 km

To solve this equation, let's cross-multiply:
3 * 1 = 2 * km
3 = 2 * km
km = 3/2 km

Conclusion:
Therefore, Ashok should cycle at a speed of 3/2 km/hr in order to reach school at 8 a.m.
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Ashok cycles from his home to his school which starts at 8 a.m. If he cycles at 6 km/hr , he would reach the school 10 minutes late. If he cycles at 8 km/hr, he would reach the school 5 min early. At what speed should he cycle to reach school at 8 a.m. ?
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Ashok cycles from his home to his school which starts at 8 a.m. If he cycles at 6 km/hr , he would reach the school 10 minutes late. If he cycles at 8 km/hr, he would reach the school 5 min early. At what speed should he cycle to reach school at 8 a.m. ? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Ashok cycles from his home to his school which starts at 8 a.m. If he cycles at 6 km/hr , he would reach the school 10 minutes late. If he cycles at 8 km/hr, he would reach the school 5 min early. At what speed should he cycle to reach school at 8 a.m. ? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ashok cycles from his home to his school which starts at 8 a.m. If he cycles at 6 km/hr , he would reach the school 10 minutes late. If he cycles at 8 km/hr, he would reach the school 5 min early. At what speed should he cycle to reach school at 8 a.m. ?.
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