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The remainder when 1010+10100+101000+....+1010000000000 is divided by 7 is
  • a)
    1
  • b)
    2
  • c)
    5
  • d)
    7
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The remainder when1010+10100+101000+....+1010000000000 is divided by 7...
Solution:

The given number is 1010 10100 101000 .... 1010000000000.

We observe that the number is formed by concatenating the numbers 10, 100, 1000, ... up to 1000000000000.

Let S be the sum of these numbers: S = 10 + 100 + 1000 + ... + 1000000000000.

We can write S as follows:

S = 10(1 + 10 + 100 + ... + 100000000000) = 10(111111111111) = 1111111111110.

Now, let's consider the remainders when the powers of 10 are divided by 7:

10^1 ≡ 3 (mod 7)
10^2 ≡ 2 (mod 7)
10^3 ≡ 6 (mod 7)
10^4 ≡ 4 (mod 7)
10^5 ≡ 5 (mod 7)
10^6 ≡ 1 (mod 7)
10^7 ≡ 3 (mod 7)
10^8 ≡ 2 (mod 7)
10^9 ≡ 6 (mod 7)
10^10 ≡ 4 (mod 7)
10^11 ≡ 5 (mod 7)
10^12 ≡ 1 (mod 7)

We observe that the remainders repeat in cycles of length 6.

Therefore, we can write the remainder when S is divided by 7 as follows:

S ≡ (3 + 2 + 6 + 4 + 5 + 1) + (3 + 2 + 6 + 4 + 5 + 1) + ... (mod 7)

There are 11 numbers in the sum, so we have:

S ≡ 11(21) ≡ 2 (mod 7)

Therefore, the remainder when 1010 10100 101000 .... 1010000000000 is divided by 7 is 5.

Hence, the correct answer is option (c) 5.
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Community Answer
The remainder when1010+10100+101000+....+1010000000000 is divided by 7...
The remainder of (1010+10100+101000+....+1010000000000)÷7→(310+3100+31000+.....+310000000000)÷7→(34+34+34+34+34+34+34+34+34+34)÷7=Remainder of 40÷7→5.
So, the correct option is C
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