Two dice are thrown together. The probability that the event the diffe...
Total number of sample space in two dice, n(s) = 6×6 =36.
let x= event of getting the number whose difference is 2
= {(1,3) , (2,4) , (3,5) , (4,6) , (3,1) , (4,2) , (5,3) , (6,4)}
n(x) = 8
p(x) = (n (x) )/ n(s) = 8/36 = 2/9
so the answer is 2/9.
Two dice are thrown together. The probability that the event the diffe...
Understanding the Problem:
When two dice are thrown together, there are a total of 36 possible outcomes (6 outcomes on the first die multiplied by 6 outcomes on the second die).
Finding the Favorable Outcomes:
To find the outcomes where the difference of the numbers shown is 2, we need to consider the following pairs of numbers:
(1,3), (2,4), (3,5), (4,6), (3,1), (4,2), (5,3), (6,4)
These pairs result in a difference of 2 between the numbers shown on the dice.
Calculating the Probability:
There are 8 favorable outcomes out of 36 possible outcomes.
Therefore, the probability of the event is:
P(difference of numbers shown is 2) = Number of favorable outcomes / Total number of outcomes
P = 8/36 = 2/9
Conclusion:
The correct answer is option 'A' (2/9), as this represents the probability that the difference of the numbers shown on the two dice is 2.