Two dice are thrown together. The probability that the event the diffe...
Total number of sample space in two dice, n(s) = 6×6 =36.
let x= event of getting the number whose difference is 2
= {(1,3) , (2,4) , (3,5) , (4,6) , (3,1) , (4,2) , (5,3) , (6,4)}
n(x) = 8
p(x) = (n (x) )/ n(s) = 8/36 = 2/9
so the answer is 2/9.
Two dice are thrown together. The probability that the event the diffe...
Understanding the Problem:
When two dice are thrown together, there are a total of 36 possible outcomes (6 outcomes on the first die multiplied by 6 outcomes on the second die).
Finding the Favorable Outcomes:
To find the outcomes where the difference of the numbers shown is 2, we need to consider the following pairs of numbers:
(1,3), (2,4), (3,5), (4,6), (3,1), (4,2), (5,3), (6,4)
These pairs result in a difference of 2 between the numbers shown on the dice.
Calculating the Probability:
There are 8 favorable outcomes out of 36 possible outcomes.
Therefore, the probability of the event is:
P(difference of numbers shown is 2) = Number of favorable outcomes / Total number of outcomes
P = 8/36 = 2/9
Conclusion:
The correct answer is option 'A' (2/9), as this represents the probability that the difference of the numbers shown on the two dice is 2.
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.