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Two dice are thrown at a time. The probability that ‘the difference of nos shown is 1’ is
- a)11/18
- b)5/18
- c)7/18
- d)none
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Two dice are thrown at a time. The probability that ‘the differe...
Correct option is A)
Possible outcomes on rolling two dices are 36
Out of the possible outcomes, chances of getting numbers with difference one are as follows : 2,1;3,2;4,3;5,4;6,5 and vice versa in each case.
⇒ Number of favourable outcomes =10
Probability = Favourable Outcomes ÷ Total Outcomes =3610=185
Possible outcomes on rolling two dices are 36
Out of the possible outcomes, chances of getting numbers with difference one are as follows : 2,1;3,2;4,3;5,4;6,5 and vice versa in each case.
⇒ Number of favourable outcomes =10
Probability = Favourable Outcomes ÷ Total Outcomes =3610=185
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Community Answer
Two dice are thrown at a time. The probability that ‘the differe...
Calculating the probability:
To find the probability that the difference of the numbers shown on two dice is 1, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
Favorable outcomes:
Let's consider the numbers on the two dice as (a, b), where a and b can take values from 1 to 6 each. The difference between the numbers will be 1 if one of the following combinations occurs:
- (1, 2), (2, 3), (3, 4), (4, 5), (5, 6)
- (2, 1), (3, 2), (4, 3), (5, 4), (6, 5)
There are a total of 10 favorable outcomes.
Total outcomes:
When two dice are thrown, the total number of outcomes is given by multiplying the number of outcomes on each die. Since each die has 6 possible outcomes, the total number of outcomes is 6 * 6 = 36.
Calculating the probability:
The probability is given by the formula:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Substituting the values, we get:
Probability = 10 / 36
Simplifying the fraction, we get:
Probability = 5 / 18
Therefore, the probability that the difference of the numbers shown on two dice is 1 is 5/18, which corresponds to option B.
To find the probability that the difference of the numbers shown on two dice is 1, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
Favorable outcomes:
Let's consider the numbers on the two dice as (a, b), where a and b can take values from 1 to 6 each. The difference between the numbers will be 1 if one of the following combinations occurs:
- (1, 2), (2, 3), (3, 4), (4, 5), (5, 6)
- (2, 1), (3, 2), (4, 3), (5, 4), (6, 5)
There are a total of 10 favorable outcomes.
Total outcomes:
When two dice are thrown, the total number of outcomes is given by multiplying the number of outcomes on each die. Since each die has 6 possible outcomes, the total number of outcomes is 6 * 6 = 36.
Calculating the probability:
The probability is given by the formula:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Substituting the values, we get:
Probability = 10 / 36
Simplifying the fraction, we get:
Probability = 5 / 18
Therefore, the probability that the difference of the numbers shown on two dice is 1 is 5/18, which corresponds to option B.
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Two dice are thrown at a time. The probability that ‘the difference of nos shown is 1’ isa)11/18b)5/18c)7/18d)noneCorrect answer is option 'B'. Can you explain this answer?
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