Two dice are rolled by two players A and B. A throws total 10 , the pr...
Answer:
Introduction:
In this question, we are given that two players A and B roll two dice each. The sum of the numbers on A's dice is 10. We need to find the probability that B's sum is more than A's sum.
Calculating the probability:
Let's first find the total number of possible outcomes when two dice are rolled. Each dice has 6 possible outcomes, so the total number of outcomes for two dice is 6 x 6 = 36.
Out of these 36 possible outcomes, we need to find the number of outcomes where the sum of the numbers on B's dice is more than 10. We can do this by listing all the possible outcomes for A's dice and then finding the number of outcomes for B's dice that satisfy the condition.
The possible outcomes for A's dice are:
- (4,6)
- (5,5)
- (6,4)
Out of these 3 possible outcomes, only one outcome has a sum of more than 10, which is (6,4). Therefore, the number of outcomes where B's sum is more than A's sum is 1.
Hence, the probability that B's sum is more than A's sum is 1/36.
Conclusion:
The correct answer is option (B) 1/36.
Two dice are rolled by two players A and B. A throws total 10 , the pr...
Since the only combinations possible higher than 10 are 6, 5 5,6 and 6,6, the actual ans will be 3/36, and when divided by 3, 1/12
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