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A potential difference of 300V is applied across a series combination of 3 muF & 9 muF capacitors. The charge on each capacitor is a-3600 muc b- 40×10^-3C c-75×10^-3C d-675muc?
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A potential difference of 300V is applied across a series combination ...
And 6 muF capacitors. Calculate the charge on the 6 muF capacitor.

We can start by finding the equivalent capacitance of the series combination:

1/Ceq = 1/C1 + 1/C2
1/Ceq = 1/3 + 1/6
1/Ceq = 1/2
Ceq = 2 muF

Now we can use the formula Q = CV to find the charge on the 6 muF capacitor:

Q = C x V
Q = 6 muF x (300 V / 2 muF)
Q = 900 uC

Therefore, the charge on the 6 muF capacitor is 900 microcoulombs.
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A potential difference of 300V is applied across a series combination of 3 muF & 9 muF capacitors. The charge on each capacitor is a-3600 muc b- 40×10^-3C c-75×10^-3C d-675muc?
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