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The sum of the series 7/2 7 21/2 14 . to 17 terms is?
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The sum of the series 7/2 7 21/2 14 . to 17 terms is?
Solution:

Given: Series is 7/2, 7, 21/2, 14 and the number of terms is 17.

We can find the sum of the series by using the formula for the sum of n terms of an arithmetic progression.

Arithmetic Progression: A sequence of numbers where each term is obtained by adding a fixed number to the previous term.

The series given is an arithmetic progression as the difference between any two consecutive terms is constant.

Formula: The sum of n terms of an arithmetic progression is given by the formula:

S_n = n/2 [2a + (n-1)d]

Where S_n is the sum of n terms, a is the first term, d is the common difference, and n is the number of terms.

Calculation:

Here, a = 7/2, d = 7 - 7/2 = 7/2 and n = 17.

Substituting these values in the formula, we get:

S_17 = 17/2 [2(7/2) + (17-1)(7/2)]

S_17 = 17/2 [7 + 16(7/2)]

S_17 = 17/2 [7 + 56]

S_17 = 17/2 x 63

S_17 = 535.5

Therefore, the sum of the given series up to 17 terms is 535.5.

Conclusion:

The sum of the given series up to 17 terms is 535.5. We used the formula for the sum of n terms of an arithmetic progression to obtain the solution.
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The sum of the series 7/2 7 21/2 14 . to 17 terms is? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The sum of the series 7/2 7 21/2 14 . to 17 terms is? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the series 7/2 7 21/2 14 . to 17 terms is?.
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