Carbon=0.24
oxygen=0.32

3x+4x = 0.56
7x = 0.56
x= 0.56/7=0.8
carbon= 3x =3*0.8 = 0.24
oxygen=4x = 4*0.8= 0.32

Introduction:
In this problem, we are given the mass ratio of Carbon to Oxygen in Carbon Monoxide and we need to determine the amount of Carbon and Oxygen required to completely combine and form a given mass of Carbon Monoxide.

Given information:
- Mass ratio of Carbon to Oxygen in Carbon Monoxide is 3:4.
- Total mass of Carbon Monoxide formed is 5.6 grams.

Step 1: Calculate the mass of Carbon:
To find the mass of Carbon in Carbon Monoxide, we can use the given mass ratio of Carbon to Oxygen.

Given mass ratio: 3:4
Let's assume the mass of Carbon is 3x.
Then, the mass of Oxygen is 4x.

The total mass of Carbon Monoxide is 5.6 grams.
So, the mass of Carbon is (3x/7) * 5.6 grams.

Step 2: Calculate the mass of Oxygen:
We already know that the mass of Oxygen is 4x.
So, the mass of Oxygen is (4x/7) * 5.6 grams.

Step 3: Solve for x:
To find the value of x, we can equate the sum of the masses of Carbon and Oxygen to the total mass of Carbon Monoxide.

(3x/7) * 5.6 grams + (4x/7) * 5.6 grams = 5.6 grams

Simplifying the equation:
3x + 4x = 5.6 * 7
7x = 39.2
x = 39.2/7
x = 5.6 grams

Step 4: Calculate the mass of Carbon and Oxygen:
Finally, we can substitute the value of x back into our expressions for the mass of Carbon and Oxygen.

Mass of Carbon = (3x/7) * 5.6 grams = (3 * 5.6)/7 grams = 2.4 grams
Mass of Oxygen = (4x/7) * 5.6 grams = (4 * 5.6)/7 grams = 3.2 grams

Conclusion:
To completely combine and form 5.6 grams of Carbon Monoxide, we need 2.4 grams of Carbon and 3.2 grams of Oxygen.