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Two cyclists start simultaneously towards each other from Aurangabad and ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at elllora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from ellora.?
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Two cyclists start simultaneously towards each other from Aurangabad a...
Problem: Two cyclists start simultaneously towards each other from Aurangabad and Ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at Ellora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from Ellora.

Solution:

Let's assume that the speed of the first cyclist who started from Aurangabad is x km/h and the speed of the second cyclist who started from Ellora is y km/h.

Distance and time calculations:
- Distance between Aurangabad and Ellora = 28km
- Time taken by the first cyclist to reach the meeting point = 1 hour
- Time taken by the second cyclist to reach the meeting point = 1 hour - 35 minutes = 25 minutes or 25/60 hours

Speed calculations:
- Speed = Distance/Time

Speed of the first cyclist = x km/h
Speed of the second cyclist = y km/h

When they meet after an hour, the total distance covered by both the cyclists is 28 km.

Therefore, we can form the following equation:

Distance covered by the first cyclist + Distance covered by the second cyclist = 28 km

x km/h * 1 hour + y km/h * 1 hour = 28 km

x + y = 28

Now, let's assume that the time taken by the second cyclist to reach Ellora is t hours.

Since the first cyclist reached Aurangabad after 1 hour, the second cyclist took (1 + t) hours to reach Ellora.

We know that the distance covered by both cyclists is the same.

Therefore, we can form another equation:

Distance covered by the first cyclist = Distance covered by the second cyclist

x km/h * (1 + t) hours = y km/h * t hours

x(1+t) = yt

x + xt = yt

t = x/(y-x)

Substituting this value of t in the equation x + y = 28, we get:

x + y = 28

x + x/(y-x) = 28

y - x = x/(28 - x)

y = x(29 - x)/(28 - x)

We know that the speed of the first cyclist is x km/h.

Therefore, the speed of the second cyclist is:

y = x(29 - x)/(28 - x)

Hence, we have found the speed of the second cyclist who started from Ellora.

Answer: The speed of the cyclist who started from Ellora is x(29 - x)/(28 - x) km/h.
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Two cyclists start simultaneously towards each other from Aurangabad and ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at elllora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from ellora.?
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Two cyclists start simultaneously towards each other from Aurangabad and ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at elllora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from ellora.? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Two cyclists start simultaneously towards each other from Aurangabad and ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at elllora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from ellora.? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two cyclists start simultaneously towards each other from Aurangabad and ellora, which are 28km apart. An hour later, they meet and keep pedaling with the same speed without stopping. The second cyclist arrives at elllora 35 min later than the first arrives at Aurangabad. Find the speed of the cyclist who started from ellora.?.
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