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A pedestrian and a cyclist start simultaneously towards each other from Aurangabad and Paithan which are 40 km apart and meet 2 hours after the start. Then they resumed their trips and the cyclist arrives at Aurangabad 7 hours 30 minutes earlier than the pedestrian arrives at Paithan. Which of these could be the speed of the pedestrian?
  • a)
    4 km/h
  • b)
    5 km/h
  • c)
    3 km/h
  • d)
    6 km/h
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A pedestrian and a cyclist start simultaneously towards each other fro...
The relative speed is 20 kmph. Also, the pedestrian should take 7:30 hours more than the cyclist.
Using option (a) the speeds of the two people are 4km/hr and 16 km/hr respectively.
At this speed, the respective times would be 10 hrs and 2:30 hours, giving the required answer.
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Community Answer
A pedestrian and a cyclist start simultaneously towards each other fro...
To solve this problem, let's break it down into two parts: the initial meeting and the subsequent travel time.

1. Initial Meeting:
- Let's assume the speed of the pedestrian is P km/h and the speed of the cyclist is C km/h.
- The time taken by the pedestrian to meet the cyclist is 2 hours.
- Thus, in these 2 hours, the pedestrian travels a distance of 2P km and the cyclist travels a distance of 2C km.
- The total distance between Aurangabad and Paithan is 40 km, so we can write the equation: 2P + 2C = 40.

2. Subsequent Travel Time:
- The cyclist arrives at Aurangabad 7 hours 30 minutes (or 7.5 hours) earlier than the pedestrian arrives at Paithan.
- Let's assume the time taken by the pedestrian to reach Paithan is T hours.
- The time taken by the cyclist to reach Aurangabad is T + 7.5 hours.
- We know that distance = speed × time, so we can write the equations: P × T = 40 and C × (T + 7.5) = 40.

Now, let's solve these equations to find the value of P.

From the equation P × T = 40, we can express T in terms of P: T = 40/P.

Substituting this value of T in the equation C × (T + 7.5) = 40, we get C × (40/P + 7.5) = 40.

Simplifying this equation, we have 40C + 7.5C = 40P.

Now, let's substitute the value of C from the first equation (2P + 2C = 40): 40(2P + 2C) + 7.5C = 40P.

Expanding this equation, we get 80P + 80C + 7.5C = 40P.

Simplifying further, we have 40P + 87.5C = 0.

Since P and C are speeds, they cannot be negative. Therefore, the only possible solution is when C = 0.

Substituting C = 0 in the first equation (2P + 2C = 40), we get 2P = 40, or P = 20/2 = 10.

However, the options provided for the speed of the pedestrian are 4 km/h, 5 km/h, 3 km/h, and 6 km/h. None of these options match the calculated speed of 10 km/h.

Hence, there seems to be an error in the given options, and we cannot determine the speed of the pedestrian with the given information.
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A pedestrian and a cyclist start simultaneously towards each other from Aurangabad and Paithan which are 40 km apart and meet 2 hours after the start. Then they resumed their trips and the cyclist arrives at Aurangabad 7 hours 30 minutes earlier than the pedestrian arrives at Paithan. Which of these could be the speed of the pedestrian?a)4 km/hb)5 km/hc)3 km/hd)6 km/hCorrect answer is option 'A'. Can you explain this answer?
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