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The Number of ways in which 12 students can be equally divided into three groups is (a) 5775 (b) 7575 (c) 7755 (d) none of these?
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The Number of ways in which 12 students can be equally divided into th...
Solution:

The given problem can be solved using combination formula.

Formula: nCr = n! / r! * (n-r)!

where n is the number of items, and r is the number of items being chosen at a time.

Step 1: Find the total number of ways to choose 4 students from 12 students.

12C4 = 12! / 4! * (12-4)! = 495

Step 2: Find the total number of ways to choose 4 students from 8 students.

8C4 = 8! / 4! * (8-4)! = 70

Step 3: Find the total number of ways to choose 4 students from 4 students.

4C4 = 1

Step 4: Multiply the number of ways in each step.

495 * 70 * 1 = 34650

Step 5: Divide the total number of ways by the number of groups.

34650 / 3! = 5775

Therefore, the number of ways in which 12 students can be equally divided into three groups is 5775.

Answer: (a) 5775
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The Number of ways in which 12 students can be equally divided into three groups is (a) 5775 (b) 7575 (c) 7755 (d) none of these?
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The Number of ways in which 12 students can be equally divided into three groups is (a) 5775 (b) 7575 (c) 7755 (d) none of these? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The Number of ways in which 12 students can be equally divided into three groups is (a) 5775 (b) 7575 (c) 7755 (d) none of these? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Number of ways in which 12 students can be equally divided into three groups is (a) 5775 (b) 7575 (c) 7755 (d) none of these?.
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