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Pressure of 200kp is equivalent to a head of x metres in a homogeneous liquid with its diameter d at the free surface the depth of centre of pressure from the free surface is?
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Pressure of 200kp is equivalent to a head of x metres in a homogeneous...
Conversion of Pressure to Head

  • Given: Pressure (P) = 200 kPa

  • Let's assume the density of the liquid as ρ

  • Acceleration due to gravity = g = 9.81 m/s²

  • Using the formula, P = ρgh, where h is the height of the liquid column

  • h = P/(ρg)

  • Now, we need to find the density of the liquid to proceed further



Density of Liquid

  • Given: Diameter (d) at the free surface

  • Let's assume the height of the liquid column as H

  • Free surface area = πd²/4

  • Volume of the liquid = πd²H/4

  • Let's assume the mass of the liquid as m

  • Mass = ρV = ρ(πd²H/4)

  • ρ = m/(πd²H/4)



Depth of Centre of Pressure

  • The depth of the centre of pressure from the free surface is given by the formula:

  • dcp = H/2 + I/Ad

  • Where I is the second moment of area of the liquid column about its centroid and A is the cross-sectional area of the column.

  • The second moment of area can be calculated using the formula:

  • I = πd⁴/64

  • Hence, dcp = H/2 + (πd²/4)(πd⁴/64)/(πd²/4)

  • dc p = H/2 + d²/16



Therefore, the depth of the centre of pressure from the free surface is equal to H/2 + d²/16.
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Pressure of 200kp is equivalent to a head of x metres in a homogeneous liquid with its diameter d at the free surface the depth of centre of pressure from the free surface is?
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