Class B Push-Pull Amplifier with Transformer Coupled Load

A push-pull amplifier is a type of amplifier that uses two complementary active devices, such as transistors or tubes, to amplify the input signal. The push-pull topology is used to reduce distortion and increase efficiency.

In this particular circuit, the load is transformer-coupled, which means that the output of the amplifier is connected to the primary winding of a transformer, and the secondary winding is connected to the load. This configuration is commonly used to match the impedance of the amplifier to the load and to provide isolation between them.

Maximum Power Output

The maximum power output of a push-pull amplifier depends on several factors, such as the supply voltage, the load impedance, and the maximum power rating of the active devices. In this case, we are given that the two transistors used in the amplifier have a maximum power rating of 10W each.

To calculate the maximum power output of the amplifier, we can use the formula:

Pmax = Vcc^2 / (8Rl)

Where Pmax is the maximum power output, Vcc is the supply voltage, and Rl is the load impedance.

Since we are not given the supply voltage or the load impedance, we cannot calculate the exact value of Pmax. However, we can use some assumptions to estimate a range of values.

Assuming a typical supply voltage of 12V and a load impedance of 8 ohms, we can calculate the maximum power output as:

Pmax = 12^2 / (8*8) = 22.5W

This is the theoretical maximum power output that can be obtained from the amplifier. However, in practice, the actual output power may be lower due to various factors such as component tolerances, thermal limitations, and distortion.

Therefore, based on the given information, the maximum power output of the amplifier is likely to be in the range of 40-50W, which corresponds to the maximum power rating of the two transistors. The correct answer is option B, 50W.