A total of 972B chocolates are distributed amongst a certain number o...
To solve this problem, we can use the concept of division.
Let's assume the number of people to be x.
According to the given information, the total number of chocolates distributed is 972B and each person receives 327B chocolates.
So, we can form the equation:
972B = 327B * x
Simplifying this equation, we get:
972 = 327 * x
Now, let's solve this equation to find the value of x (the number of people).
Dividing both sides of the equation by 327:
972/327 = 327x/327
Simplifying:
2.97 = x
Since the number of people cannot be a decimal, we need to round off the value of x.
Now, let's check the given options to find the correct value of B.
a) 13
b) 14
c) 17
d) 19
Substituting the calculated value of x into the equation:
972 = 327 * 2.97
972 = 965.19
Since the calculated value does not match the given total number of chocolates, we can conclude that the value of x should be rounded up to the nearest whole number.
So, x = 3.
Now, let's substitute this value of x into the equation to find the value of B.
972 = 327 * 3B
972 = 981B
Dividing both sides of the equation by 981:
972/981 = 981B/981
Simplifying:
0.99 = B
Since B cannot be a decimal, we need to round off the value of B.
The only option that matches the calculated value of B is 19 (option d), so the correct answer is option d) 19.
A total of 972B chocolates are distributed amongst a certain number o...
972B=9B2+7B+2 and 327B=3B2+2B+7 Now, 4(3B2+2B+7)=12B2+8B+28 which is much greater than 9B2+7B+2
Hence, 972B must be either the 2 nd or 3 rd multiple of 327B Now, 2(3B2+2B+7)=6B2+4B+14 If 972B is the 2 nd multiple of 327B, then 9B2+7B+2=6B2+4B+14 3B2+3B−12=0
Here, we do not get any integral value of B.
Hence, 972B must be the 3 rd multiple of 327B 9B2+7B+2=3(3B2+2B+7)
B = 19
Hence, option 4.
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