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Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion?
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Two forces are acting on a 10 kg blocks as shown in figure show block ...
The work done on a block by the resulting force can be calculated using the equation:
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the resulting force acting on the block
- Distance is the distance over which the force is applied
- theta is the angle between the force and the direction of motion
To solve this problem, we need to calculate the magnitude of the resulting force and the distance over which it acts.
1. Finding the Resulting Force:
To find the resulting force, we need to calculate the net force acting on the block. In this case, there are two forces acting on the block: the applied force (F_applied) and the frictional force (F_friction).
The applied force can be calculated using Newton's second law:
F_applied = mass * acceleration
Given that the mass of the block is 10 kg and the block is moving with a velocity of 14.66 m/s, we can calculate the acceleration using the equation:
velocity^2 = initial velocity^2 + 2 * acceleration * distance
Rearranging the equation, we have:
acceleration = (velocity^2 - initial velocity^2) / (2 * distance)
Assuming the initial velocity is 0, the acceleration becomes:
acceleration = (14.66^2) / (2 * distance)
Now, we can calculate the applied force:
F_applied = 10 kg * (14.66^2) / (2 * distance)
The frictional force can be calculated using the equation:
F_friction = coefficient of friction * normal force
The normal force is equal to the weight of the block, which can be calculated as:
normal force = mass * gravity
Given that the mass of the block is 10 kg and the acceleration due to gravity is 9.8 m/s^2, we can calculate the normal force:
normal force = 10 kg * 9.8 m/s^2
Now, we can calculate the frictional force:
F_friction = 0.2 * (10 kg * 9.8 m/s^2)
The resulting force is the difference between the applied force and the frictional force:
Resulting force = F_applied - F_friction
2. Finding the Distance:
To find the distance over which the force is applied, we need more information. The given problem does not provide any information about the distance traveled by the block. Without this information, it is not possible to calculate the work done on the block.
Therefore, it is not possible to determine the work done on the block by the resulting force without knowing the distance traveled.
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the resulting force acting on the block
- Distance is the distance over which the force is applied
- theta is the angle between the force and the direction of motion
To solve this problem, we need to calculate the magnitude of the resulting force and the distance over which it acts.
1. Finding the Resulting Force:
To find the resulting force, we need to calculate the net force acting on the block. In this case, there are two forces acting on the block: the applied force (F_applied) and the frictional force (F_friction).
The applied force can be calculated using Newton's second law:
F_applied = mass * acceleration
Given that the mass of the block is 10 kg and the block is moving with a velocity of 14.66 m/s, we can calculate the acceleration using the equation:
velocity^2 = initial velocity^2 + 2 * acceleration * distance
Rearranging the equation, we have:
acceleration = (velocity^2 - initial velocity^2) / (2 * distance)
Assuming the initial velocity is 0, the acceleration becomes:
acceleration = (14.66^2) / (2 * distance)
Now, we can calculate the applied force:
F_applied = 10 kg * (14.66^2) / (2 * distance)
The frictional force can be calculated using the equation:
F_friction = coefficient of friction * normal force
The normal force is equal to the weight of the block, which can be calculated as:
normal force = mass * gravity
Given that the mass of the block is 10 kg and the acceleration due to gravity is 9.8 m/s^2, we can calculate the normal force:
normal force = 10 kg * 9.8 m/s^2
Now, we can calculate the frictional force:
F_friction = 0.2 * (10 kg * 9.8 m/s^2)
The resulting force is the difference between the applied force and the frictional force:
Resulting force = F_applied - F_friction
2. Finding the Distance:
To find the distance over which the force is applied, we need more information. The given problem does not provide any information about the distance traveled by the block. Without this information, it is not possible to calculate the work done on the block.
Therefore, it is not possible to determine the work done on the block by the resulting force without knowing the distance traveled.
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Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion?
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Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion?.
Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two forces are acting on a 10 kg blocks as shown in figure show block adults velocity of root 14.66m/s after travelling some distance if block perform motion only in horizontal direction and kinetic friction of surface is 0.2 find the work done on a block by resulting for during the motion?.
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