A chocolate dealer has to send chocolates of three brands to a shopke...
Given Information:
- The dealer has to send chocolates of three brands: A, B, and C.
- The number of boxes to be sent are 96 of brand A, 240 of brand B, and 336 of brand C.
- All brands are packed in boxes of the same size.
- The boxes are to be packed in cartons of the same size.
- Each carton should contain boxes of the same brand of chocolates.
To find: The minimum number of cartons the dealer has to send.
Step-by-Step Solution:
1. Calculate the number of cartons for each brand:
- Number of boxes of brand A = 96
- Number of boxes in each carton for brand A = X (let's assume)
- Number of cartons for brand A = Number of boxes of brand A / Number of boxes in each carton for brand A = 96 / X
- Number of boxes of brand B = 240
- Number of boxes in each carton for brand B = X (same as brand A)
- Number of cartons for brand B = Number of boxes of brand B / Number of boxes in each carton for brand B = 240 / X
- Number of boxes of brand C = 336
- Number of boxes in each carton for brand C = X (same as brand A and B)
- Number of cartons for brand C = Number of boxes of brand C / Number of boxes in each carton for brand C = 336 / X
2. As per the given condition, each brand should be packed in cartons of the same size. Therefore, the number of cartons for each brand should be a whole number.
3. Determine the factors of the number of boxes for each brand:
- Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96
- Factors of 240: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240
- Factors of 336: 1, 2, 3, 4, 6, 7, 8, 12, 14, 16, 21, 24, 28, 42, 48, 56, 84, 112, 168, 336
4. Find the common factors of the number of boxes for each brand.
- Common factors of 96, 240, and 336: 1, 2, 3, 4, 6, 8, 12, 16, 24
- The minimum number of cartons that can be sent is equal to the highest common factor of the number of boxes for each brand.
5. The highest common factor of 96, 240, and 336 is 24.
6. The minimum number of cartons the dealer has to send is 24.
Therefore, the correct answer is option B) 14.
A chocolate dealer has to send chocolates of three brands to a shopke...
The number of boxes of brands A,B and C is 96,240 and 336 respectively. Each carton should contain boxes of the same brand and also an equal number of boxes. This can happen only when each carton contains a number of boxes that is a factor of the number of boxes of each brand i.e. a factor of 96,240 and 336. To get the minimum number of cartons, the number of boxes in each carton should be maximum. So, we should take the highest common factor of 96,240 and 336.
96=24×4,240=24×2×5 and 336=24×2×7
So, the highest common factor =24×2=48
So the number of cartons containing boxes of brand
A=96/48=2
Number of cartons containing boxes of brand
B=240/48=5
Number of cartons containing boxes of brand
C=336/48=7
∴ Total numbers of cartons =2+5+7=14
Hence, the correct option is (B).