In how many different ways can the letters of the word ‘THERAPY’ be a...
Introduction:
In this problem, we are given the word 'THERAPY' and we need to find the number of different ways we can arrange its letters such that the vowels (E, A) never come together.
Approach:
To solve this problem, we can use the concept of permutations and combinations. We will calculate the total number of arrangements of all the letters and then subtract the number of arrangements where the vowels come together.
Step 1: Calculate the total number of arrangements:
The word 'THERAPY' has 7 letters. The number of ways we can arrange these 7 letters is given by 7!.
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040
So, there are 5040 different ways to arrange the letters of the word 'THERAPY' without any restrictions.
Step 2: Calculate the number of arrangements where vowels come together:
To calculate the number of arrangements where the vowels (E, A) come together, we can consider them as a single unit. So, we have 6 units to arrange: T, H, R, P, Y, (EA).
The number of ways we can arrange these 6 units is given by 6!.
6! = 6 x 5 x 4 x 3 x 2 x 1 = 720
However, within the (EA) unit, the vowels can be arranged in 2! = 2 ways.
So, the total number of arrangements where the vowels come together is 720 x 2 = 1440.
Step 3: Calculate the number of arrangements where vowels never come together:
To calculate the number of arrangements where the vowels never come together, we subtract the number of arrangements where the vowels come together from the total number of arrangements.
Number of arrangements where vowels never come together = Total number of arrangements - Number of arrangements where vowels come together
= 5040 - 1440
= 3600
Conclusion:
Therefore, the number of different ways we can arrange the letters of the word 'THERAPY' such that the vowels never come together is 3600.
In how many different ways can the letters of the word ‘THERAPY’ be a...
Total no. of cases = 7!
There are two vowels, E and A.
Considering them as one word, total number of possible words = 6!, and the two letters can be arranged among themselves in 2! Ways.
So, number of cases where vowels will be together = 6! × 2!
So, total no of ways when vowels never come together = 7!- (6! × 2!) = 3600
Hence, the correct option is (d).
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