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In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?
- a)20°
- b)30°
- c)40°
- d)50°
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In the figure given below, ABC is a triangle. BC is parallel to AE. If...
Given that, BC || AE
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
Most Upvoted Answer
In the figure given below, ABC is a triangle. BC is parallel to AE. If...
Given that, BC || AE
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
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Community Answer
In the figure given below, ABC is a triangle. BC is parallel to AE. If...
Given that, BC || AE
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵ BC = AC
Hence, ΔABC is an isosceles triangle.
⇒ ∠CBA = ∠CAB = 65°
Now, ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.
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In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of∠CAE?a)20°b)30°c)40°d)50°Correct answer is option 'D'. Can you explain this answer?
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