ABC and BDC are two triangles as shown in the given figure. If BDC is ...
Since BD = CD,AngleDBC = AngleDCB (Let them be x)
Now three sides of triangles sums up to 180.AngleABC + AngleCBA + AngleCAB = 18040 +40+50+x+x = 180solving this, x = 25.
in triangle DBC,25+25+AngleDBC = 180angleDBC = 130
ABC and BDC are two triangles as shown in the given figure. If BDC is ...
Given:-ABC and BDC are two triangles
Now BDC is isoceles triangle
BD=DC
To find:- Angle BDC =?
Solution:- Since BD=DC
Using Isoceles triangle property,
Angle DBC = Angle DCB = Angle 'x'
[We are naming it as X for our. convenience]
Now, In triangle ABC,
Angle A + Angle B + Angle C = 180 degree
[Using angle sum property of triangle]
=> 40degree + (40+x)degree + (50+x)degree =180 degree
=> 2x=180 degree-130 degree
=> 2x=50degree
=>x=25 degree
Again, In triangle BDC,
Using angle aum property of triangle,
Angle BDC + Angle DBC + Angle DCB =180 degree
Angle BDC + 25 degree + 25 degree =180 degree
Angle BDC= 180 degree - 50degree
Angle BDC = 130 degree
Hence, Correct answer is option D