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In the given figure AB || CD, ∠ALC = 60° and EC is the bisector of ∠LCD. If EF || AB then the value of ∠CEF is


  • a)
    120°

  • b)
    140°

  • c)
    150°

  • d)
    None of these

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In the given figure AB || CD, ∠ALC = 60° and EC is the bisecto...

∠ALC = ∠LCD = 60°
[∵  Alternate angles]
EC is the bisector of ∠LCD
∴ ∠ ECD = (1 / 2) × ∠ LCD
= (1 / 2) × 60º = 30º
∠CEF + ∠ECD = 180°
[∵  Pair of interior angles]
∠CEF + 30° = 180°
∠CEF = 180° – 30° = 150°
Hence, option C is correct.
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Most Upvoted Answer
In the given figure AB || CD, ∠ALC = 60° and EC is the bisecto...

∠ALC = ∠LCD = 60°
[∵  Alternate angles]
EC is the bisector of ∠LCD
∴ ∠ ECD = (1 / 2) × ∠ LCD
= (1 / 2) × 60º = 30º
∠CEF + ∠ECD = 180°
[∵  Pair of interior angles]
∠CEF + 30° = 180°
∠CEF = 180° – 30° = 150°
Hence, option C is correct.
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In the given figure AB || CD, ∠ALC = 60° and EC is the bisector of ∠LCD. If EF || AB then the value of ∠CEF isa)120°b)140°c)150°d)None of theseCorrect answer is option 'C'. Can you explain this answer?
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