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A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?
- a)15
- b)30
- c)25
- d)40
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A vessel contains 75 liters of milk and water in the ratio of 3:2. If...
Given:
Initial mixture: 75 liters (milk:water = 3:2)
After adding x liters of milk and (x-5) liters of water: (milk:water = 4:3)
Let's solve this step by step:
1. Initial mixture:
The ratio of milk to water in the initial mixture is 3:2. So, we can write:
Milk = (3/5) * Total volume
Water = (2/5) * Total volume
Given that the total volume is 75 liters, we can substitute the values:
Milk = (3/5) * 75 = 45 liters
Water = (2/5) * 75 = 30 liters
2. After adding x liters of milk and (x-5) liters of water:
The ratio of milk to water becomes 4:3. So, we can write:
Milk = (4/7) * Total volume
Water = (3/7) * Total volume
Since x liters of milk and (x-5) liters of water are added, the new total volume will be:
Total volume = 75 + x + (x-5) = 2x + 70 liters
Substituting the values in terms of total volume:
Milk = (4/7) * (2x + 70)
Water = (3/7) * (2x + 70)
3. Equating the two expressions for milk and water:
Since the ratio of milk to water is the same in both cases, we can equate the expressions:
(3/5) * 75 = (4/7) * (2x + 70)
Simplifying this equation will give us the value of x.
Let's solve it:
(3/5) * 75 = (4/7) * (2x + 70)
225/5 = (8/7) * (2x + 70)
45 = (8/7) * (2x + 70)
45 * (7/8) = 2x + 70
315/8 - 70 = 2x
35/8 = 2x
x = (35/8) * (1/2)
x = 35/16
Now, we need to find the value of (x-5):
x - 5 = 35/16 - 5 = (35 - 80)/16 = -45/16 = -2.8125 (approx.)
Since we cannot have a negative value for liters, we can conclude that the value of (x-5) is 0.
Therefore, the value of (x-5) is 0, which is option D.
Initial mixture: 75 liters (milk:water = 3:2)
After adding x liters of milk and (x-5) liters of water: (milk:water = 4:3)
Let's solve this step by step:
1. Initial mixture:
The ratio of milk to water in the initial mixture is 3:2. So, we can write:
Milk = (3/5) * Total volume
Water = (2/5) * Total volume
Given that the total volume is 75 liters, we can substitute the values:
Milk = (3/5) * 75 = 45 liters
Water = (2/5) * 75 = 30 liters
2. After adding x liters of milk and (x-5) liters of water:
The ratio of milk to water becomes 4:3. So, we can write:
Milk = (4/7) * Total volume
Water = (3/7) * Total volume
Since x liters of milk and (x-5) liters of water are added, the new total volume will be:
Total volume = 75 + x + (x-5) = 2x + 70 liters
Substituting the values in terms of total volume:
Milk = (4/7) * (2x + 70)
Water = (3/7) * (2x + 70)
3. Equating the two expressions for milk and water:
Since the ratio of milk to water is the same in both cases, we can equate the expressions:
(3/5) * 75 = (4/7) * (2x + 70)
Simplifying this equation will give us the value of x.
Let's solve it:
(3/5) * 75 = (4/7) * (2x + 70)
225/5 = (8/7) * (2x + 70)
45 = (8/7) * (2x + 70)
45 * (7/8) = 2x + 70
315/8 - 70 = 2x
35/8 = 2x
x = (35/8) * (1/2)
x = 35/16
Now, we need to find the value of (x-5):
x - 5 = 35/16 - 5 = (35 - 80)/16 = -45/16 = -2.8125 (approx.)
Since we cannot have a negative value for liters, we can conclude that the value of (x-5) is 0.
Therefore, the value of (x-5) is 0, which is option D.
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Community Answer
A vessel contains 75 liters of milk and water in the ratio of 3:2. If...
The quantity of milk in the vessel initially = 75 * 3/(3 + 2) = 75 * 3/5 = 45 liters
The quantity of water in the vessel initially = 75 – 45 = 30 liters
(45 + x)/(30 + x – 5) = 4/3
135 + 3x = 120 + 4x – 20
x = 35
Required value = 35 + 5 = 40
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A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer?.
A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer?.
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A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A vessel contains 75 liters of milk and water in the ratio of 3:2. If x liters of milk and (x-5) liters of water is added to the mixture, then the ratio of milk to water becomes 4:3. Find the value of (x+5)?a)15b)30c)25d)40e)None of theseCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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