Two friends A and B leave City P and City Q simultaneously and travel...
Let us assume Car A travels at a speed of a and Car B travels at a speed of b.
Further, let us assume that they meet after t minutes.
Distance traveled by car A before meeting car B = a × t. Likewise distance traveled by car B before meeting car A = b × t.
Distance traveled by car A after meeting car B = a × 54. Distance traveled by car B after meeting car A = 24 × b.
Distance traveled by car A after crossing car B = distance traveled by car B before crossing car A (and vice versa).
⇒ at = 54b ---------- (1)
and bt = 24a -------- (2)
Multiplying equations 1 and 2
we have ab × t2 = 54 × 24 × ab
⇒ t2 = 54 × 24
⇒ t = 36
So, both cars would have traveled 36 minutes prior to crossing each other. Or, B would have taken 36 + 24 = 60 minutes to travel the whole distance.
Hence, the correct option is (c).