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The Laurent series expansion of the function valid in the region 0 < |z| < 2, is given by
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The Laurent series expansion of the function valid in the region 0 <...

ex – 1 has a zero at ‘0’ of multiplicity one and hence f(z) has pole at 0 of order 1. So, the Laurent series f(z) is given by

Since (ez – 1) f(z) = 1

By comparing both the sides,
a-1 = 1
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The Laurent series expansion of the function valid in the region 0 <...

ex – 1 has a zero at ‘0’ of multiplicity one and hence f(z) has pole at 0 of order 1. So, the Laurent series f(z) is given by

Since (ez – 1) f(z) = 1

By comparing both the sides,
a-1 = 1
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The Laurent series expansion of the function valid in the region 0 < |z| < 2, is given bya)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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