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For a thysistor maximum junction temperature is 200°C. The thermal resistance for the thyristor sink combination are θJC= 0.15 andθCS= 0.05c/w. Initially the heat sink temperature of 80° C and it is brought down to 70° C by force cooling, the percentage increase in the device rating is – (in%)Correct answer is between '4,4.1'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For a thysistor maximum junction temperature is 200°C. The thermal resistance for the thyristor sink combination are θJC= 0.15 andθCS= 0.05c/w. Initially the heat sink temperature of 80° C and it is brought down to 70° C by force cooling, the percentage increase in the device rating is – (in%)Correct answer is between '4,4.1'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a thysistor maximum junction temperature is 200°C. The thermal resistance for the thyristor sink combination are θJC= 0.15 andθCS= 0.05c/w. Initially the heat sink temperature of 80° C and it is brought down to 70° C by force cooling, the percentage increase in the device rating is – (in%)Correct answer is between '4,4.1'. Can you explain this answer?.

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