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A switch is connected in between a 12 V battery and an uncharged capacitor and a 1 KΩ resistor. At the time instant when the switch is closed, the voltage across the capacitor is:
  • a)
    6 V
  • b)
    12 V
  • c)
    0 V
  • d)
    24 V
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A switch is connected in between a 12 V battery and an uncharged capac...
Ω resistor, as shown in the circuit below:

Battery (+12V) ---[Switch]--- [Capacitor] ---[Resistor]--- Ground

When the switch is closed, the capacitor begins to charge. The time constant of this RC circuit is given by the product of the resistance and the capacitance (RC). In this case, the time constant is 1KΩ * C, where C is the capacitance in farads.

The time constant determines how quickly the capacitor charges. Specifically, it is the time it takes for the capacitor to charge to approximately 63.2% of its final voltage.

If we want to calculate the time it takes for the capacitor to charge to 99% of its final voltage, we can use the formula:

t = -RC * ln(1 - 0.99)

In this case, the final voltage is 12V, so we can plug in the values:

t = -1KΩ * C * ln(1 - 0.99)

To calculate the time it takes for the capacitor to charge to 99% of its final voltage, we need to know the capacitance value. Can you provide the capacitance value?
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Community Answer
A switch is connected in between a 12 V battery and an uncharged capac...
Concept:
A capacitor doesn’t allow a sudden change in voltage across it, i.e.
Vc(0-) = Vc(0+)
Calculation:
Given circuit can be drawn as:
⇒ Vc(0-) = 0V (because the switch is open)
At t = 0+ (i.e. at the instant when the switch is closed)
Vc(0+) = 0 V
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A switch is connected in between a 12 V battery and an uncharged capacitor and a 1 KΩ resistor. At the time instant when the switch is closed, the voltage across the capacitor is:a)6 Vb)12 Vc)0 Vd)24 VCorrect answer is option 'C'. Can you explain this answer?
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