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In the given figure, O is centre of the larger circle of radius 10 cm while P is the centre of the smaller circle. If AB = 10√2 cm, find the area of segment ABC lying outside the smaller circle.
  • a)
    22.5π – 25
  • b)
    22.5π – 50
  • c)
    45π – 50
  • d)
    45π – 50
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the given figure, O is centre of the larger circle of radius 10 cm...
Let OC meet AB at D, as we have right triangle ODB
So, OD2 + DB2 = OB2.
OB = 10, DB =
So, OD= 5√2
Now in triangle ODB, OD=DB and similarly OD=AD.
So, we can say ∠B = ∠DOB = 450
Similarly ∠C = ∠DOC = 450
So, ∠AOB = 900
So, area of sector AOB = 1/4 π (10)2 = 25π
Area of segment ABC = Area of sector AOB - area of triangle OAB = 25π- 1/2 x10 x10
= 25π - 50
Area of segment ABC lying outside smaller circle is area of segment ABC - area of smaller circle
Now for smaller circle diameter is DC and we have OC = OD + DC DC = 10 - 5√2.
So, radius of smaller circle is
So, the required area =
= (25√2 - 12.5) π - 50 = 22.5π – 50.
Hence, the correct option is (b).
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DIRECTIONSfor the question:Read the passage and answer the question based on it.The tale of reading begins when the retina receives photons reflected off the written page. But the retina is not a homogeneous sensor. Only its central part, called the fovea, is dense in high-resolution cells sensitive to incoming light, while the rest of the retina has a coarser resolution. The fovea, which occupies about 15 degrees of the visual field, is the only part of the retina that is genuinely useful for reading. When foveal information is lacking, whether due to a retinal lesion, to a stroke having destroyed the central part of the visual cortex, or to an experimental trick that selectively blocks visual inputs to the fovea, reading becomes impossible."The need to bring words into the fovea explains why our eyes are in constant motion when we read. By orienting our gaze, we "scan" text with the most sensitive part of our vision, the only one that has the resolution needed to determine letters. 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In the given figure, O is centre of the larger circle of radius 10 cm while P is the centre of the smaller circle. If AB = 10√2 cm, find the area of segment ABC lying outside the smaller circle.a)22.5π – 25b)22.5π – 50c)45π – 50d)45π – 50Correct answer is option 'B'. Can you explain this answer?
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