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A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.?
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A cylindrical specimen of saturated clay 4cm in diameter and 9cm in ...
Given data:
- Diameter of the clay specimen (D) = 4 cm
- Overall length of the clay specimen (L) = 9 cm
- Length between the apices of cones (L') = 8 cm
- Axial load at failure (P) = 46.5 N
- Change in length at failure (ΔL) = 1 cm
Calculations:
1. Cross-sectional area of the specimen:
The cross-sectional area of the cylindrical specimen can be calculated using the formula:
A = π * (D/2)^2
Substituting the given values:
A = π * (4/2)^2 = 12.57 cm²
2. Unconfined compressive strength:
The unconfined compressive strength (UCS) is calculated using the formula:
UCS = P / A
Substituting the given values:
UCS = 46.5 N / 12.57 cm² = 3.70 N/cm²
3. Strain at failure:
Strain (ε) is the change in length (ΔL) divided by the original length (L):
ε = ΔL / L
Substituting the given values:
ε = 1 cm / 9 cm = 0.111
4. Stress at failure:
Stress (σ) can be calculated using the formula:
σ = UCS * ε
Substituting the calculated values:
σ = 3.70 N/cm² * 0.111 = 0.41 N/cm²
Explanation:
1. The given data provides the dimensions and properties of the cylindrical clay specimen tested in an unconfined compression test.
2. The unconfined compressive strength (UCS) is a measure of the maximum axial stress that a specimen can withstand without any lateral confinement.
3. The cross-sectional area of the specimen is calculated using its diameter, and the unconfined compressive strength is determined by dividing the axial load at failure by the cross-sectional area.
4. The strain at failure is calculated by dividing the change in length at failure by the original length of the specimen.
5. The stress at failure is obtained by multiplying the unconfined compressive strength by the strain at failure.
6. In this case, the unconfined compressive strength of the clay specimen is calculated to be 3.70 N/cm², and the stress at failure is 0.41 N/cm².
Summary:
The unconfined compressive strength of the clay specimen is determined to be 3.70 N/cm², and the stress at failure is calculated to be 0.41 N/cm². These values provide an indication of the clay's ability to withstand axial loading without any lateral confinement. The calculations are based on the given dimensions of the specimen and the axial load and change in length at failure.
- Diameter of the clay specimen (D) = 4 cm
- Overall length of the clay specimen (L) = 9 cm
- Length between the apices of cones (L') = 8 cm
- Axial load at failure (P) = 46.5 N
- Change in length at failure (ΔL) = 1 cm
Calculations:
1. Cross-sectional area of the specimen:
The cross-sectional area of the cylindrical specimen can be calculated using the formula:
A = π * (D/2)^2
Substituting the given values:
A = π * (4/2)^2 = 12.57 cm²
2. Unconfined compressive strength:
The unconfined compressive strength (UCS) is calculated using the formula:
UCS = P / A
Substituting the given values:
UCS = 46.5 N / 12.57 cm² = 3.70 N/cm²
3. Strain at failure:
Strain (ε) is the change in length (ΔL) divided by the original length (L):
ε = ΔL / L
Substituting the given values:
ε = 1 cm / 9 cm = 0.111
4. Stress at failure:
Stress (σ) can be calculated using the formula:
σ = UCS * ε
Substituting the calculated values:
σ = 3.70 N/cm² * 0.111 = 0.41 N/cm²
Explanation:
1. The given data provides the dimensions and properties of the cylindrical clay specimen tested in an unconfined compression test.
2. The unconfined compressive strength (UCS) is a measure of the maximum axial stress that a specimen can withstand without any lateral confinement.
3. The cross-sectional area of the specimen is calculated using its diameter, and the unconfined compressive strength is determined by dividing the axial load at failure by the cross-sectional area.
4. The strain at failure is calculated by dividing the change in length at failure by the original length of the specimen.
5. The stress at failure is obtained by multiplying the unconfined compressive strength by the strain at failure.
6. In this case, the unconfined compressive strength of the clay specimen is calculated to be 3.70 N/cm², and the stress at failure is 0.41 N/cm².
Summary:
The unconfined compressive strength of the clay specimen is determined to be 3.70 N/cm², and the stress at failure is calculated to be 0.41 N/cm². These values provide an indication of the clay's ability to withstand axial loading without any lateral confinement. The calculations are based on the given dimensions of the specimen and the axial load and change in length at failure.
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A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.?
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A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.?.
A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.?.
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A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.?, a detailed solution for A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? has been provided alongside types of A cylindrical specimen of saturated clay 4cm in diameter and 9cm in overall length is tested in an unconfined compression enter.The specimen has coned ends and its length between the apices of cones is 8cm . Find the unconfined compressive strength of clay . If the specimen fails under an axial load of 46.5N . The change in the length of specimen at failure is 1cm.? theory, EduRev gives you an
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