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In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 3rd harmonic from the output voltage waveform, the value of the pulse width (2d) must be
  • a)
  • b)
    60°
  • c)
    120°
  • d)
    180°
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In case of a single-pulse width modulation with the pulse width = 2d, ...
The value of the pulse width (2d) cannot be zero in order to eliminate the 3rd harmonic from the output voltage waveform. The 3rd harmonic can be eliminated by setting the pulse width to a value that is a multiple of the period of the 3rd harmonic.
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Community Answer
In case of a single-pulse width modulation with the pulse width = 2d, ...
To eliminate the nth harmonic, nd = π.
Therefore, d = π/n = π/3 = 60°
Hence, 2d = 120°.
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In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 3rd harmonic from the output voltage waveform, the value of the pulse width (2d) must bea)0°b)60°c)120°d)180°Correct answer is option 'C'. Can you explain this answer?
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