Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > The magnetic potential energy stored in a cer...
Start Learning for Free
The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:
- a)0.138 H
- b)138.88 H
- c)1.389 H
- d)13.89 H
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The magnetic potential energy stored in a certain inductor is 25 mJ, w...
Concept:
- The coil which stores magnetic energy in a magnetic field is called an inductor.
- The property of an inductor which causes the emf to generate by a change in electric current is called as inductance of the inductor.
- The SI unit of inductance is Henry (H).
- The magnetic potential energy stored in an inductor is given by,
Where L is inductance of the inductor and I is current flowing.
Explanation:
Given that:
Magnetic potential energy (U) = 25 mJ = 25 x 10-3 J
Current (I) = 60 mA = 60 x 10-3A
Use the formula:
Given that:
Magnetic potential energy (U) = 25 mJ = 25 x 10-3 J
Current (I) = 60 mA = 60 x 10-3A
Use the formula:
Free Test
FREE
| Start Free Test |
Community Answer
The magnetic potential energy stored in a certain inductor is 25 mJ, w...
Calculating Inductance:
- The magnetic potential energy stored in an inductor is given by the formula:
\[W = \frac{1}{2}LI^2\]
where:
W = magnetic potential energy stored (25 mJ = 25 x 10^-3 J)
L = inductance of the inductor (to be calculated)
I = current in the inductor (60 mA = 60 x 10^-3 A)
- Substituting the given values into the formula:
\[25 x 10^-3 J = \frac{1}{2}L(60 x 10^-3 A)^2\]
Solving for Inductance:
- Rearranging the formula to solve for inductance:
\[L = \frac{2W}{I^2}\]
\[L = \frac{2(25 x 10^-3)}{(60 x 10^-3)^2}\]
\[L = \frac{50 x 10^-3}{3600 x 10^-6}\]
\[L = \frac{50}{3600} H\]
\[L = 13.89 H\]
Therefore, the inductance of the inductor is 13.89 H, which corresponds to option 'D'.
- The magnetic potential energy stored in an inductor is given by the formula:
\[W = \frac{1}{2}LI^2\]
where:
W = magnetic potential energy stored (25 mJ = 25 x 10^-3 J)
L = inductance of the inductor (to be calculated)
I = current in the inductor (60 mA = 60 x 10^-3 A)
- Substituting the given values into the formula:
\[25 x 10^-3 J = \frac{1}{2}L(60 x 10^-3 A)^2\]
Solving for Inductance:
- Rearranging the formula to solve for inductance:
\[L = \frac{2W}{I^2}\]
\[L = \frac{2(25 x 10^-3)}{(60 x 10^-3)^2}\]
\[L = \frac{50 x 10^-3}{3600 x 10^-6}\]
\[L = \frac{50}{3600} H\]
\[L = 13.89 H\]
Therefore, the inductance of the inductor is 13.89 H, which corresponds to option 'D'.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer?
Question Description
The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer?.
The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer?.
Solutions for The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance:a)0.138 Hb)138.88 Hc)1.389 Hd)13.89 HCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup