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In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?
- a)140 A
- b)440 A
- c)160 A
- d)150 A
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a 110 V DC chopper drive using the CLC scheme, the maximum possible...
Introduction:
In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is given as 300 A, and the lower limit of the current pulsation is given as 140 A. We need to determine the maximum limit of the current pulsation.
Understanding the Chopper Drive:
A chopper drive is an electronic circuit that controls the speed and direction of a DC motor. It uses a chopper switch to control the average voltage applied to the motor, thereby controlling its speed. The CLC scheme stands for Constant Load Current scheme, which is a common control strategy used in chopper drives.
Calculating the Maximum Limit of Current Pulsation:
The current pulsation in a chopper drive is the difference between the maximum and minimum current levels. In this case, the maximum possible value of the accelerating current is given as 300 A, and the lower limit of the current pulsation is given as 140 A.
To calculate the maximum limit of current pulsation, we need to subtract the lower limit of current pulsation from the maximum possible value of the accelerating current:
Maximum limit of current pulsation = Maximum possible value of accelerating current - Lower limit of current pulsation
= 300 A - 140 A
= 160 A
Conclusion:
Therefore, the maximum limit of current pulsation in the given 110 V DC chopper drive using the CLC scheme is 160 A. Hence, option C (160 A) is the correct answer.
In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is given as 300 A, and the lower limit of the current pulsation is given as 140 A. We need to determine the maximum limit of the current pulsation.
Understanding the Chopper Drive:
A chopper drive is an electronic circuit that controls the speed and direction of a DC motor. It uses a chopper switch to control the average voltage applied to the motor, thereby controlling its speed. The CLC scheme stands for Constant Load Current scheme, which is a common control strategy used in chopper drives.
Calculating the Maximum Limit of Current Pulsation:
The current pulsation in a chopper drive is the difference between the maximum and minimum current levels. In this case, the maximum possible value of the accelerating current is given as 300 A, and the lower limit of the current pulsation is given as 140 A.
To calculate the maximum limit of current pulsation, we need to subtract the lower limit of current pulsation from the maximum possible value of the accelerating current:
Maximum limit of current pulsation = Maximum possible value of accelerating current - Lower limit of current pulsation
= 300 A - 140 A
= 160 A
Conclusion:
Therefore, the maximum limit of current pulsation in the given 110 V DC chopper drive using the CLC scheme is 160 A. Hence, option C (160 A) is the correct answer.
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In a 110 V DC chopper drive using the CLC scheme, the maximum possible...
Current Limit Control of Chopper (CLC):
In this strategy, the chopper is turned on when the output current i0 equals a preset value I2.
The chopper is kept on till i0 increases to another preset value I1.
The chopper is turned off when i0 equals I1 and is kept off till the current i0 decays to I2.
The current i0 is thus limited to a maximum of I1 and a minimum of I2 as shown in Figure.
The chopping frequency and the pulse width are dependent on the load parameters.
The advantage of current limit control is that the ripple (I1 - I2), in the load current i0 can be adjusted to a small, predetermined value for a wide range of loads.
Application:
Given,
The maximum possible value of the accelerating current (I2) = 300 A
Current pulsation or current ripple (ΔI) = 140 A
The waveform can be drawn as,
From the waveform,
The maximum limit of current pulsation (I2) = I1 + ΔI = 300 + 140 = 440 A
In this strategy, the chopper is turned on when the output current i0 equals a preset value I2.
The chopper is kept on till i0 increases to another preset value I1.
The chopper is turned off when i0 equals I1 and is kept off till the current i0 decays to I2.
The current i0 is thus limited to a maximum of I1 and a minimum of I2 as shown in Figure.
The chopping frequency and the pulse width are dependent on the load parameters.
The advantage of current limit control is that the ripple (I1 - I2), in the load current i0 can be adjusted to a small, predetermined value for a wide range of loads.
Application:
Given,
The maximum possible value of the accelerating current (I2) = 300 A
Current pulsation or current ripple (ΔI) = 140 A
The waveform can be drawn as,
From the waveform,
The maximum limit of current pulsation (I2) = I1 + ΔI = 300 + 140 = 440 A
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In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer?.
In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer?.
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In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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