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The work done in an open vessel at 300 k, when 112 g iron reacts with dil HCL to give FeCl2, is nearly 1)1.1Kcal 2)0.6 Kcal 3)0.3 Kcal 4) 0.2 Kcal
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The work done in an open vessel at 300 k, when 112 g iron reacts with ...
The work done in an open vessel at 300 K when 112 g of iron reacts with dilute hydrochloric acid (HCl) to give FeCl2 can be calculated using the equation:

Work done = -PΔV

Where P is the pressure and ΔV is the change in volume.

1. Calculation of moles of iron:
The first step is to calculate the number of moles of iron (Fe) present in the given mass.
The molar mass of iron (Fe) is 55.845 g/mol.
Therefore, the number of moles of Fe = (mass of Fe) / (molar mass of Fe)
= 112 g / 55.845 g/mol
≈ 2 moles

2. Calculation of moles of FeCl2:
The balanced chemical equation for the reaction of iron with HCl is:
Fe + 2HCl → FeCl2 + H2
According to the balanced equation, 1 mole of Fe reacts to give 1 mole of FeCl2.
Therefore, the number of moles of FeCl2 formed = 2 moles

3. Calculation of work done:
In an open vessel, the pressure remains constant, so the work done can be calculated as:
Work done = -PΔV
Since the pressure remains constant, PΔV is equal to ΔnRT, where Δn is the change in the number of moles, R is the ideal gas constant, and T is the temperature.

Δn = (moles of product) - (moles of reactant)
= (2 moles) - (0 moles) (since Fe is not a gas)
= 2 moles

R = 0.0821 L·atm/mol·K (ideal gas constant)
T = 300 K (temperature)

Work done = -PΔV
= -ΔnRT
= -(2 moles)(0.0821 L·atm/mol·K)(300 K)
≈ -49.26 L·atm

To convert L·atm to calories, we can use the conversion factor:
1 L·atm = 101.3 J
1 J = 0.239005736 calories

Therefore, work done = -49.26 L·atm × (101.3 J / 1 L·atm) × (0.239005736 calories / 1 J)
≈ -1180.73 calories

The negative sign indicates that work is done on the system (exothermic reaction). To convert calories to kilocalories, divide by 1000.

Therefore, work done = -1180.73 calories / 1000
≈ -1.18 kcal

Since the question asks for the approximate value, we can round it to 1.2 kcal.

Therefore, the work done in the open vessel at 300 K when 112 g of iron reacts with dilute HCl to give FeCl2 is nearly 1.2 kcal.
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The work done in an open vessel at 300 k, when 112 g iron reacts with dil HCL to give FeCl2, is nearly 1)1.1Kcal 2)0.6 Kcal 3)0.3 Kcal 4) 0.2 Kcal
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