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The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).
Correct answer is between '0.74,0.76'. Can you explain this answer?
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Most Upvoted Answer
The baseband signal m(t) shown in the figure is phase-modulated to gen...
Concept:
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
if θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
if θ (t) = 2π fct + k m(t)Calculation:
Given Φ(t) = cos (2π fct + km(t))
fc = 50 kHz
K = 10 π
Phase of the modulated signal is given by:
θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
is the slope of the message signal:
maximum positive slope (between 0 ≤ t ≤ 1) is 2
Maximum negative slope (between +1 < t < 3) is:
= -2/2 = -1
fi max = 50 + 5(2) = 60 kHz
fi min = 50 – 5(1) = 45 kHz
Given Φ(t) = cos (2π fct + km(t))
fc = 50 kHz
K = 10 π
Phase of the modulated signal is given by:
θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
is the slope of the message signal:maximum positive slope (between 0 ≤ t ≤ 1) is 2
Maximum negative slope (between +1 < t < 3) is:
= -2/2 = -1
fi max = 50 + 5(2) = 60 kHz
fi min = 50 – 5(1) = 45 kHz
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Community Answer
The baseband signal m(t) shown in the figure is phase-modulated to gen...
Concept:
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as: if θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
if θ (t) = 2π fct + k m(t)Calculation:
Given Φ(t) = cos (2π fct + km(t))
fc = 50 kHz
K = 10 π
Phase of the modulated signal is given by:
θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
is the slope of the message signal:
maximum positive slope (between 0 ≤ t ≤ 1) is 2
Maximum negative slope (between +1 < t < 3) is:
= -2/2 = -1
fi max = 50 + 5(2) = 60 kHz
fi min = 50 – 5(1) = 45 kHz
Given Φ(t) = cos (2π fct + km(t))
fc = 50 kHz
K = 10 π
Phase of the modulated signal is given by:
θ (t) = 2π fct + k m(t)
The instantaneous angular frequency will be obtained by differentiating the instantaneous phase as:
is the slope of the message signal:maximum positive slope (between 0 ≤ t ≤ 1) is 2
Maximum negative slope (between +1 < t < 3) is:
= -2/2 = -1
fi max = 50 + 5(2) = 60 kHz
fi min = 50 – 5(1) = 45 kHz
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The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer?
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The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer?.
The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The baseband signal m(t) shown in the figure is phase-modulated to generate the PM signal φ(t) = cos(2πfct + km(t)). The time t on the x-axis in the figure is in milliseconds. If the carrier frequency fc = 50 kHz and k = 10π, then the ratio of the minimum instantaneous frequency (in kHz) to the maximum instantaneous frequency (in kHz) is __________ (rounded off to 2 decimal places).Correct answer is between '0.74,0.76'. Can you explain this answer?.
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