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A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?
- a)0.99% negative feedback
- b)0.99% positive feedback
- c)1% negative feedback
- d)1% positive feedback
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the...
Given:
- Bandwidth of the practical op-amp = 10 Hz
- Gain = 10^6
- Required bandwidth = 100 kHz
To find:
- Amount of feedback required
Solution:
1. Understanding the concept of feedback:
- Feedback is a technique used in amplifiers to control the gain and other performance parameters.
- It involves feeding back a fraction of the output signal to the input of the amplifier.
2. Types of feedback:
- Negative feedback: The output signal is subtracted from the input signal, resulting in a negative feedback.
- Positive feedback: The output signal is added to the input signal, resulting in a positive feedback.
3. Relationship between gain and feedback:
- The gain of an amplifier with feedback is given by the formula:
Gain (with feedback) = Gain (without feedback) / (1 + (Gain (without feedback) * Feedback))
4. Calculation:
- Given: Bandwidth of the practical op-amp = 10 Hz
- To achieve the required bandwidth of 100 kHz, the gain of the amplifier needs to be reduced.
- Let's assume the amount of feedback required is 'x'.
- Using the formula for gain with feedback, we can write:
Gain (with feedback) = Gain (without feedback) / (1 + (Gain (without feedback) * Feedback))
- Substituting the given values, we get:
10^6 = 10^6 / (1 + (10^6 * x))
- Simplifying the equation, we get:
1 + (10^6 * x) = 1
10^6 * x = 0
x = 0
- The amount of feedback required is 0% or 0.00%.
5. Conversion to percentage:
- The required feedback can be converted to a percentage by multiplying it by 100.
- 0% feedback is equivalent to 0% negative feedback.
6. Answer:
- The correct answer is option 'A': 0.99% negative feedback.
- Bandwidth of the practical op-amp = 10 Hz
- Gain = 10^6
- Required bandwidth = 100 kHz
To find:
- Amount of feedback required
Solution:
1. Understanding the concept of feedback:
- Feedback is a technique used in amplifiers to control the gain and other performance parameters.
- It involves feeding back a fraction of the output signal to the input of the amplifier.
2. Types of feedback:
- Negative feedback: The output signal is subtracted from the input signal, resulting in a negative feedback.
- Positive feedback: The output signal is added to the input signal, resulting in a positive feedback.
3. Relationship between gain and feedback:
- The gain of an amplifier with feedback is given by the formula:
Gain (with feedback) = Gain (without feedback) / (1 + (Gain (without feedback) * Feedback))
4. Calculation:
- Given: Bandwidth of the practical op-amp = 10 Hz
- To achieve the required bandwidth of 100 kHz, the gain of the amplifier needs to be reduced.
- Let's assume the amount of feedback required is 'x'.
- Using the formula for gain with feedback, we can write:
Gain (with feedback) = Gain (without feedback) / (1 + (Gain (without feedback) * Feedback))
- Substituting the given values, we get:
10^6 = 10^6 / (1 + (10^6 * x))
- Simplifying the equation, we get:
1 + (10^6 * x) = 1
10^6 * x = 0
x = 0
- The amount of feedback required is 0% or 0.00%.
5. Conversion to percentage:
- The required feedback can be converted to a percentage by multiplying it by 100.
- 0% feedback is equivalent to 0% negative feedback.
6. Answer:
- The correct answer is option 'A': 0.99% negative feedback.
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Community Answer
A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the...
B2 = B1(1+βA) = 10(1+β106) = 100k
1 + β106 = 10k
β = 9.999×10-3
In percentage, feedback β = 0.99% negative feedback.
1 + β106 = 10k
β = 9.999×10-3
In percentage, feedback β = 0.99% negative feedback.
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A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer?
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A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer?.
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A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required?a)0.99% negative feedbackb)0.99% positive feedbackc)1% negative feedbackd)1% positive feedbackCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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