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Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:
  • a)
    (1100010.11)2 (246.6)8 and (62.C)16
  • b)
    (0100011.11)2 (142.6)8 and (62.C)16
  • c)
    (0100011.11)2 (242.6)8 and (62.12)16
  • d)
    (1100010.11)2 (142.6)8 and (62.C)16
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Conversion of (98.75)10 into binary, octal and hexadecimal number syst...
Concept:
Conversion of decimal to binary:
Step 1: Divide the number by 2 keeping notice of the quotient and the remainder. Continue dividing the quotient by 2 until you get a quotient of zero.
Step 2: Write out the remainders in the reverse order to get the equivalent binary number.
For converting decimal fractions to binary numbers, follow these steps:
For converting decimal fractions to a binary numbers, follow these steps:
Then write out the integer parts from the results of each multiplication to get the equivalent binary number.
Conversion of binary to octal:
Make pair of three binary number which forms an octal number.
Conversion of binary to hexadecimal:
Make pair of four binary number which forms a hexadecimal number.
Calculation:
Given, that the decimal number = (98.75)10 
98 / 2 = 49 with remainder 0
49 / 2 = 24 with remainder 1
24 / 2 = 12 with remainder 0
12 / 2 = 6 with remainder 0
6 / 2 = 3 with remainder 0
3 / 2 = 1 with remainder 1
1 / 2 = 0 with remainder 1
Write in reverse order:
98 = 1100010
0.75 × 2 = 1 + 0.5
0.5 × 2 = 1 + 0
.75 = .11
(98.75)10 = (1100010.11)
(98.75)10 = (001  100  010.  110)2 = (142.6)8 ...........(from table 1)
(98.75)10 = (0110  0010.  1100)2 = (62.C)16...........(from table 2)
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Community Answer
Conversion of (98.75)10 into binary, octal and hexadecimal number syst...
Conversion of Decimal to Binary
To convert the decimal number (98.75)10 into binary:
1. Whole Number Part (98)10
- Divide by 2 and keep track of the remainders:
- 98 ÷ 2 = 49 remainder 0
- 49 ÷ 2 = 24 remainder 1
- 24 ÷ 2 = 12 remainder 0
- 12 ÷ 2 = 6 remainder 0
- 6 ÷ 2 = 3 remainder 0
- 3 ÷ 2 = 1 remainder 1
- 1 ÷ 2 = 0 remainder 1
- Reading from bottom to top gives (1100010)2.
2. Fractional Part (0.75)10
- Multiply by 2 and take the integer part:
- 0.75 × 2 = 1.5 (integer part 1)
- 0.5 × 2 = 1.0 (integer part 1)
- Thus, (0.75)10 = (0.11)2.
- Combined: (1100010.11)2.
Conversion of Decimal to Octal
To convert (98.75)10 to octal:
1. Whole Number Part (98)10
- Divide by 8:
- 98 ÷ 8 = 12 remainder 2
- 12 ÷ 8 = 1 remainder 4
- 1 ÷ 8 = 0 remainder 1
- Reading from bottom to top gives (142)8.
2. Fractional Part (0.75)10
- Multiply by 8:
- 0.75 × 8 = 6.0 (integer part 6)
- Thus, (0.75)10 = (0.6)8.
- Combined: (142.6)8.
Conversion of Decimal to Hexadecimal
To convert (98.75)10 to hexadecimal:
1. Whole Number Part (98)10
- Divide by 16:
- 98 ÷ 16 = 6 remainder 2
- Thus, (62)16.
2. Fractional Part (0.75)10
- Multiply by 16:
- 0.75 × 16 = 12.0 (integer part 12, which is C in hex)
- Thus, (0.75)10 = (0.C)16.
Final Results
- Binary: (1100010.11)2
- Octal: (142.6)8
- Hexadecimal: (62.C)16
Thus, the correct answer is option 'D'.
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Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:a)(1100010.11)2 (246.6)8 and (62.C)16b)(0100011.11)2 (142.6)8 and (62.C)16c)(0100011.11)2 (242.6)8 and (62.12)16d)(1100010.11)2 (142.6)8 and (62.C)16Correct answer is option 'D'. Can you explain this answer?
Question Description
Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:a)(1100010.11)2 (246.6)8 and (62.C)16b)(0100011.11)2 (142.6)8 and (62.C)16c)(0100011.11)2 (242.6)8 and (62.12)16d)(1100010.11)2 (142.6)8 and (62.C)16Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:a)(1100010.11)2 (246.6)8 and (62.C)16b)(0100011.11)2 (142.6)8 and (62.C)16c)(0100011.11)2 (242.6)8 and (62.12)16d)(1100010.11)2 (142.6)8 and (62.C)16Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:a)(1100010.11)2 (246.6)8 and (62.C)16b)(0100011.11)2 (142.6)8 and (62.C)16c)(0100011.11)2 (242.6)8 and (62.12)16d)(1100010.11)2 (142.6)8 and (62.C)16Correct answer is option 'D'. Can you explain this answer?.
Solutions for Conversion of (98.75)10 into binary, octal and hexadecimal number system, respectively, is:a)(1100010.11)2 (246.6)8 and (62.C)16b)(0100011.11)2 (142.6)8 and (62.C)16c)(0100011.11)2 (242.6)8 and (62.12)16d)(1100010.11)2 (142.6)8 and (62.C)16Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
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