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A 183 – bus power system has 150 PQ buses and 32 PV buses. In the general case, to obtain the load flow solution using Newton – Raphson method in polar coordinates, the minimum number of simultaneous equations to be solved is_________.
    Correct answer is '332.00'. Can you explain this answer?
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    A 183 – bus power system has 150 PQ buses and 32 PV buses. In th...
    Concept:
    The minimum number of simultaneous equations will be
    E = (2 × number of Load bus) + number of Generator buses
    Calculation:
    Given,
    The number of load buses = 150
    The number of generator buses = 32
    Minimum no. of simultaneous equations
    E = (2 × 150) + 32 = 332
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    A 183 – bus power system has 150 PQ buses and 32 PV buses. In th...
    Concept:
    The minimum number of simultaneous equations will be
    E = (2 × number of Load bus) + number of Generator buses
    Calculation:
    Given,
    The number of load buses = 150
    The number of generator buses = 32
    Minimum no. of simultaneous equations
    E = (2 × 150) + 32 = 332
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    Community Answer
    A 183 – bus power system has 150 PQ buses and 32 PV buses. In th...
    183 is a three-digit number. It is an odd number and is also a prime number. The factors of 183 are 1 and 183.
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    A 183 – bus power system has 150 PQ buses and 32 PV buses. In the general case, to obtain the load flow solution using Newton – Raphson method in polar coordinates, the minimum number of simultaneous equations to be solved is_________.Correct answer is '332.00'. Can you explain this answer?
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    Solutions for A 183 – bus power system has 150 PQ buses and 32 PV buses. In the general case, to obtain the load flow solution using Newton – Raphson method in polar coordinates, the minimum number of simultaneous equations to be solved is_________.Correct answer is '332.00'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
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