Given:
- The sum of an infinite geometric progression (G.P.) with positive terms is 48.
- The sum of the first two terms is 36.

To find:
The second term of the G.P.

Approach:
Let's use the formula for the sum of an infinite G.P. to solve this problem.

Formula:
The sum of an infinite G.P. with first term 'a' and common ratio 'r' is given by the formula:
S = a / (1 - r), where S is the sum.

Solution:
Let's assume the first term of the G.P. as 'a' and the common ratio as 'r'.

Step 1: Write the given information as equations:
- The sum of the G.P. is 48: a / (1 - r) = 48
- The sum of the first two terms is 36: a + ar = 36

Step 2: Solve the equations simultaneously:
We have two equations with two variables. Let's solve them to find the values of 'a' and 'r'.

From the second equation, we can express 'a' in terms of 'r':
a = 36 - ar

Substitute this value of 'a' in the first equation:
(36 - ar) / (1 - r) = 48

Simplify the equation:
36 - ar = 48 - 48r
36 - ar = 48(1 - r)
36 - ar = 48 - 48r

Rearrange the equation:
12r - ar = 12

Factor out 'r' from the left side:
r(12 - a) = 12

Since 'r' is not equal to 0, we can divide both sides by (12 - a):
r = 12 / (12 - a)

Step 3: Substitute the value of 'r' in terms of 'a' into the second equation and solve for 'a':
a + a(12 / (12 - a)) = 36

Simplify the equation:
a(1 + 12 / (12 - a)) = 36

Combine the terms:
a((12 - a + 12) / (12 - a)) = 36
a(24 - a) / (12 - a) = 36

Cross-multiply:
a(24 - a) = 36(12 - a)

Expand and simplify:
24a - a^2 = 432 - 36a

Rearrange the equation:
a^2 + 24a - 432 = 0

Factorize the quadratic equation:
(a - 12)(a + 36) = 0

From the equation, we have two possible values for 'a':
a = 12 or a = -36

Step 4: Verify the value of 'a' using the first equation:
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Step 5: Calculate the value of 'r':
Substitute a = 12 in

Let 'a' be the first term and 'r' be the common ratio of the G.P. We have