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In an infinite GP, every term is 7 times the sum of all terms that follow. If sum of first and second terms is 9, find the first term of G.P.

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In an infinite GP, every term is 7 times the sum of all terms that fol...

Given Information:
- Sum of first and second terms = 9
- Each term is 7 times the sum of all terms that follow

Let's assume the first term of the GP is 'a' and the common ratio is 'r'. Therefore, the second term will be ar.

Sum of first and second terms:
a + ar = 9
a(1 + r) = 9

Each term is 7 times the sum of all terms that follow:
a = 7(ar + ar^2 + ar^3 + ...)
a = 7ar(1 + r + r^2 + ...)
a = 7ar/(1 - r)

Substitute the value of a from the second equation into the first equation:
7ar/(1 - r) = 9
7r = 9 - 9r
16r = 9
r = 9/16

Substitute the value of r back into the equation a = 7ar/(1 - r):
a = 7*(9/16)/(1 - 9/16)
a = 63/16*(16/7)
a = 9

Therefore, the first term of the GP is 9.
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In an infinite GP, every term is 7 times the sum of all terms that follow. If sum of first and second terms is 9, find the first term of G.P.?
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