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In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, the first-order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.208)
- a)0.0749 nm
- b)0.0374 nm
- c)0.779 nm
- d)0.374 nm
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
In the X-ray diffraction of a set of crystal planes having d equal to ...
Concept:
Bragg’s Law states that when an X-ray beam are allowed to scatter through a crystalline surface, its angle of incidence θ will reflect with some angle of scattering θ. And when the path difference d is equal to a whole number n, of wavelength.
It can be represented as
2dsinθ =nλ
Calculation:
Given:
d = 0.18 nm, n = 1, θ = 22°
⇒ 2 × 0.18 × sin 22° = 1 ⋅ λ
⇒ λ = 0.07488 nm
Bragg’s Law states that when an X-ray beam are allowed to scatter through a crystalline surface, its angle of incidence θ will reflect with some angle of scattering θ. And when the path difference d is equal to a whole number n, of wavelength.
It can be represented as
2dsinθ =nλ
Calculation:
Given:
d = 0.18 nm, n = 1, θ = 22°
⇒ 2 × 0.18 × sin 22° = 1 ⋅ λ
⇒ λ = 0.07488 nm
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In the X-ray diffraction of a set of crystal planes having d equal to ...
To calculate the interplanar spacing (d) using X-ray diffraction, we can use Bragg's law:
n * λ = 2 * d * sin(θ)
Where:
- n is the order of reflection (in this case, first-order, so n = 1)
- λ is the wavelength of the X-ray radiation
- d is the interplanar spacing
- θ is the angle of reflection
We need to rearrange the formula to solve for d:
d = n * λ / (2 * sin(θ))
Given:
- n = 1 (first-order reflection)
- θ = 22°
The wavelength of X-ray radiation depends on the type of X-ray source used. Let's assume we are using copper Kα radiation, which has a wavelength of 1.5418 Å (angstroms) or 0.15418 nm.
Plugging in the values into the formula:
d = 1 * 0.15418 nm / (2 * sin(22°))
Using a calculator:
d ≈ 0.15418 nm / (2 * 0.374607)
d ≈ 0.15418 nm / 0.749214
d ≈ 0.205978 nm
Therefore, the interplanar spacing (d) of the crystal planes is approximately 0.206 nm.
n * λ = 2 * d * sin(θ)
Where:
- n is the order of reflection (in this case, first-order, so n = 1)
- λ is the wavelength of the X-ray radiation
- d is the interplanar spacing
- θ is the angle of reflection
We need to rearrange the formula to solve for d:
d = n * λ / (2 * sin(θ))
Given:
- n = 1 (first-order reflection)
- θ = 22°
The wavelength of X-ray radiation depends on the type of X-ray source used. Let's assume we are using copper Kα radiation, which has a wavelength of 1.5418 Å (angstroms) or 0.15418 nm.
Plugging in the values into the formula:
d = 1 * 0.15418 nm / (2 * sin(22°))
Using a calculator:
d ≈ 0.15418 nm / (2 * 0.374607)
d ≈ 0.15418 nm / 0.749214
d ≈ 0.205978 nm
Therefore, the interplanar spacing (d) of the crystal planes is approximately 0.206 nm.
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In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, the first-order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.208)a)0.0749 nmb)0.0374 nmc)0.779 nmd)0.374 nmCorrect answer is option 'A'. Can you explain this answer?
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In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, the first-order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.208)a)0.0749 nmb)0.0374 nmc)0.779 nmd)0.374 nmCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, the first-order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.208)a)0.0749 nmb)0.0374 nmc)0.779 nmd)0.374 nmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the X-ray diffraction of a set of crystal planes having d equal to 0.18 nm, the first-order reflection is found to be at an angle of 22°. The wavelength of X-rays is: (sin 22° = 0.208)a)0.0749 nmb)0.0374 nmc)0.779 nmd)0.374 nmCorrect answer is option 'A'. Can you explain this answer?.
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