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The parabolic arc y = √x, 1 ≤ x ≤ 2 is revolved around the x-axis. The volume of the solid of revolution is
  • a)
    π/4
  • b)
    π/2
  • c)
    3π/4
  • d)
    3π/2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The parabolic arc y = √x, 1 ≤ x ≤ 2 is revolved around the...
X^2 is a U-shaped curve that opens upwards. The vertex of the parabola is at the origin (0,0) and the axis of symmetry is the y-axis. The graph of the parabola passes through the point (1,1), (2,4), (-1,1), and (-2,4) as shown below.

![Parabolic Arc](https://www.mathsisfun.com/algebra/images/parabola-vertex.gif)
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Community Answer
The parabolic arc y = √x, 1 ≤ x ≤ 2 is revolved around the...
Revolution about x-axis: The volume of the solid generated by the revolution about the x-axis, of the area bounded by the curve
y = f(x), the x-axis and the ordinates
x = a and x = b is
similarly for revolution about y-axis:
V=∫πx2dy
Calculation:
Given:
V = 3π / 2
Hence the required volume will be
3π / 2.
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The parabolic arc y = √x, 1 ≤ x ≤ 2 is revolved around the x-axis. The volume of the solid of revolution isa)π/4b)π/2c)3π/4d)3π/2Correct answer is option 'D'. Can you explain this answer?
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