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Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :
- a)4 : 9
- b)9 : 5
- c)11 : 4
- d)5 : 10
Correct answer is option 'C'. Can you explain this answer?
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Three containers whose volumes are in the ratio of 2 : 3 : 4 are full ...
Ratio of Volumes and Mixtures
The given problem involves three containers with volumes in the ratio of 2:3:4, and each container contains a mixture of spirit and water in different ratios. The objective is to find the ratio of spirit and water in the resultant mixture when all the three mixtures are mixed in a big container.
Let us first calculate the volumes of the three containers using the given ratio. Let the volumes of the three containers be 2x, 3x, and 4x, respectively.
Container 1
The ratio of spirit and water in the 1st container is given as 4:1.
Let the quantity of the mixture in the 1st container be y.
The quantity of spirit in the mixture is (4/5) y, and the quantity of water is (1/5) y.
Container 2
The ratio of spirit and water in the 2nd container is given as 11:4.
Let the quantity of the mixture in the 2nd container be z.
The quantity of spirit in the mixture is (11/15) z, and the quantity of water is (4/15) z.
Container 3
The ratio of spirit and water in the 3rd container is given as 7:3.
Let the quantity of the mixture in the 3rd container be w.
The quantity of spirit in the mixture is (7/10) w, and the quantity of water is (3/10) w.
Mixing the Three Containers
When all the three mixtures are mixed in a big container, the quantities of spirit and water in the resultant mixture can be calculated as follows:
The total quantity of the mixture in the big container is y + z + w.
The total quantity of spirit in the mixture is (4/5) y + (11/15) z + (7/10) w.
The total quantity of water in the mixture is (1/5) y + (4/15) z + (3/10) w.
Ratio of Spirit and Water
The ratio of spirit and water in the resultant mixture can be calculated by dividing the total quantity of spirit by the total quantity of water.
(4/5) y + (11/15) z + (7/10) w
---------------------------------------------------
(1/5) y + (4/15) z + (3/10) w
Simplifying this expression, we get:
44y + 33z + 42w
-------------------
15y + 8z + 9w
Since the volumes of the three containers are in the ratio of 2:3:4, we can assume that y = 2a, z = 3a, and w = 4a, where a is a constant.
Substituting these values in the expression for the ratio of spirit and water, we get:
(44y + 33z + 42w)/(15y + 8z + 9w) = (44(2a) + 33(3a) + 42(4a))/(15(2a) + 8(3a) + 9(4a)) = 11/4.
Therefore, the ratio of spirit and water in the resultant mixture is 11:4.
The given problem involves three containers with volumes in the ratio of 2:3:4, and each container contains a mixture of spirit and water in different ratios. The objective is to find the ratio of spirit and water in the resultant mixture when all the three mixtures are mixed in a big container.
Let us first calculate the volumes of the three containers using the given ratio. Let the volumes of the three containers be 2x, 3x, and 4x, respectively.
Container 1
The ratio of spirit and water in the 1st container is given as 4:1.
Let the quantity of the mixture in the 1st container be y.
The quantity of spirit in the mixture is (4/5) y, and the quantity of water is (1/5) y.
Container 2
The ratio of spirit and water in the 2nd container is given as 11:4.
Let the quantity of the mixture in the 2nd container be z.
The quantity of spirit in the mixture is (11/15) z, and the quantity of water is (4/15) z.
Container 3
The ratio of spirit and water in the 3rd container is given as 7:3.
Let the quantity of the mixture in the 3rd container be w.
The quantity of spirit in the mixture is (7/10) w, and the quantity of water is (3/10) w.
Mixing the Three Containers
When all the three mixtures are mixed in a big container, the quantities of spirit and water in the resultant mixture can be calculated as follows:
The total quantity of the mixture in the big container is y + z + w.
The total quantity of spirit in the mixture is (4/5) y + (11/15) z + (7/10) w.
The total quantity of water in the mixture is (1/5) y + (4/15) z + (3/10) w.
Ratio of Spirit and Water
The ratio of spirit and water in the resultant mixture can be calculated by dividing the total quantity of spirit by the total quantity of water.
(4/5) y + (11/15) z + (7/10) w
---------------------------------------------------
(1/5) y + (4/15) z + (3/10) w
Simplifying this expression, we get:
44y + 33z + 42w
-------------------
15y + 8z + 9w
Since the volumes of the three containers are in the ratio of 2:3:4, we can assume that y = 2a, z = 3a, and w = 4a, where a is a constant.
Substituting these values in the expression for the ratio of spirit and water, we get:
(44y + 33z + 42w)/(15y + 8z + 9w) = (44(2a) + 33(3a) + 42(4a))/(15(2a) + 8(3a) + 9(4a)) = 11/4.
Therefore, the ratio of spirit and water in the resultant mixture is 11:4.
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Spirit Milk Total Capacity Ratio
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Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer?
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Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer?.
Solutions for Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC CGL.
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ample number of questions to practice Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container the ratio of spirit and water is 4 : 1 in 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7:3. All the three mixtures are mixed in a big container. The ratio of spirit and water in the resultant mixture is :a)4 : 9b)9 : 5c)11 : 4d)5 : 10Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice SSC CGL tests.
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