The minimum number of comparators required to build an 8 bit flash ADC...
Minimum number of comparators required to build an 8-bit flash ADC:
To understand the minimum number of comparators required to build an 8-bit flash ADC, let's first understand the working principle of a flash ADC and how it converts an analog input signal into a digital output.
Working Principle of a Flash ADC:
A flash ADC, also known as a parallel ADC, is a type of analog-to-digital converter that uses a combination of comparators to convert an analog input signal into a digital output. The input signal is compared to multiple reference voltages simultaneously, and the output of each comparator is used to directly generate the digital output.
Binary Encoding:
In an 8-bit flash ADC, the digital output is represented in binary form. Each bit represents a voltage range, and the output of each comparator determines whether the input signal is greater or less than the corresponding reference voltage.
Number of Comparators:
The number of comparators required for an 8-bit flash ADC can be calculated using the formula:
Number of Comparators = 2^n - 1
Where 'n' is the number of bits. In this case, n = 8.
Calculation:
Number of Comparators = 2^8 - 1
Number of Comparators = 256 - 1
Number of Comparators = 255
Therefore, the minimum number of comparators required to build an 8-bit flash ADC is 255.
Conclusion:
An 8-bit flash ADC requires a minimum of 255 comparators to accurately convert an analog input signal into a digital output. Each comparator compares the input signal with a specific reference voltage, and their outputs are combined to generate the digital representation of the input signal.
The minimum number of comparators required to build an 8 bit flash ADC...
Concept:
Flash Type ADC:
1) It is the fastest ADC among all the ADC types.
2) An n-bit flash type ADC requires:
2n -1 comparators, 2n resistors and one 2n × n priority encoder.
Calculation:
The number of comparators required to build an 8-bit flash ADC will be:
N = 28 - 1
N = 256 - 1
N = 255