Minimum Number of NAND Gates Required to Realize the Given Boolean Expression: F = A'B CD' B'CCorrect

Explanation:
To determine the minimum number of NAND gates required to realize the given boolean expression, we need to simplify the expression and convert it into an equivalent expression using only NAND gates.

Step 1: Simplify the Expression
The given boolean expression is F = A'B CD' B'CCorrect. Let's simplify it using basic boolean algebra rules:

F = A'B CD' B'CCorrect
= A'B CD' B' C'

Step 2: Convert to NAND Gates
To convert the expression into an equivalent expression using only NAND gates, we can use De Morgan's theorem and the NAND gate's ability to perform any boolean operation.

F = A'B CD' B' C'
= (A'B)' (CD')' (B')' (C')'
= (A + B)' (C + D)' (B + B)' (C + C)'

Step 3: Implement the Expression using NAND Gates
Now, we can implement the simplified expression using NAND gates. Each NAND gate can be represented as a combination of NOT and AND gates.

F = (A + B)' (C + D)' (B + B)' (C + C)'
= (A NAND B) (C NAND D) (B NAND B) (C NAND C)

Step 4: Determine the Minimum Number of NAND Gates
To determine the minimum number of NAND gates required, we count the number of NAND gate symbols in the expression:

(A NAND B) (C NAND D) (B NAND B) (C NAND C)

We have a total of 4 NAND gates in the expression.

Therefore, the minimum number of NAND gates required to realize the given boolean expression F = A'B CD' B'CCorrect is 4.

Final Answer:
The minimum number of NAND gates required is 4.