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The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage, Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.
    Correct answer is between '400,403'. Can you explain this answer?
    Verified Answer
    The figure shows the per-phase equivalent circuit of a two-pole three-...
    Exact Equivalent Circuit

    Here, R1 is the winding resistance of the stator
    X1 is the inductance of the stator winding
    R0 is the core loss component
    XM is the magnetizing reaction of the winding
    R2/s is the power of the rotor, which includes output mechanical power and loss of rotor
    Important:
    If we draw the circuit with refereed to the stator then the circuit will look like

    Here all the other parameters are same except R2’ is the rotor winding resistance with referred to stator winding. R2(1-s) / s is the resistance which shows the power which is mechanical power output or useful power. The power dissipated in that resistor is the useful power output or shaft power.
    Explanation:

    We redraw the given circuit as
    Given Vg=210V,s=0.05
    Air gap voltage is the voltage across AB, i.e.

    Hence, torque = 
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    Most Upvoted Answer
    The figure shows the per-phase equivalent circuit of a two-pole three-...
    Exact Equivalent Circuit

    Here, R1 is the winding resistance of the stator
    X1 is the inductance of the stator winding
    R0 is the core loss component
    XM is the magnetizing reaction of the winding
    R2/s is the power of the rotor, which includes output mechanical power and loss of rotor
    Important:
    If we draw the circuit with refereed to the stator then the circuit will look like

    Here all the other parameters are same except R2’ is the rotor winding resistance with referred to stator winding. R2(1-s) / s is the resistance which shows the power which is mechanical power output or useful power. The power dissipated in that resistor is the useful power output or shaft power.
    Explanation:

    We redraw the given circuit as
    Given Vg=210V,s=0.05
    Air gap voltage is the voltage across AB, i.e.

    Hence, torque = 
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    The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage,Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.Correct answer is between '400,403'. Can you explain this answer?
    Question Description
    The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage,Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.Correct answer is between '400,403'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage,Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.Correct answer is between '400,403'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage,Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.Correct answer is between '400,403'. Can you explain this answer?.
    Solutions for The figure shows the per-phase equivalent circuit of a two-pole three-phase induction motor operating at 50 Hz. The “air-gap” voltage,Vg across the magnetizing inductance, is 210 V rms, and the slip, is 0.05. The torque (in Nm) produced by the motor is _______.Correct answer is between '400,403'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
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