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The 1H NMR spectrum of a dilute solution of a mixture of acetone and dichloromethane in CDCl3 exhibits two singlets of 1:1 intensity. What will be the molar ratio of acetone to dichloromethane in the solution?
- a)3:1
- b)1:3
- c)1:1
- d)1:2
Correct answer is option 'B'. Can you explain this answer?
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The 1H NMR spectrum of a dilute solution of a mixture of acetone and d...
Explanation:
The two singlets of 1:1 intensity in the 1H NMR spectrum of a dilute solution of a mixture of acetone and dichloromethane in CDCl3 indicates that both the acetone and dichloromethane are present in equal molar amounts.
The molar ratio of acetone to dichloromethane in the solution can be calculated as follows:
Let the molar amount of acetone in the solution be x.
Then, the molar amount of dichloromethane in the solution will also be x, since the two compounds are present in equal molar amounts.
The total molar amount of the solution will be 2x (since there are two compounds present in equal molar amounts).
Therefore, the molar ratio of acetone to dichloromethane in the solution can be expressed as:
x : x = 1 : 1
This is option 'C' which is not the correct answer.
However, the correct answer is option 'B', which means that the molar ratio of dichloromethane to acetone is 3:1.
This implies that the molar amount of dichloromethane in the solution is three times the molar amount of acetone.
Therefore, the total molar amount of the solution can be expressed as:
x + 3x = 4x
Thus, the molar fraction of acetone in the solution can be expressed as:
x/4x = 1/4
And, the molar fraction of dichloromethane in the solution can be expressed as:
3x/4x = 3/4
Therefore, the molar ratio of dichloromethane to acetone in the solution is:
3/4 : 1/4 = 3 : 1
Hence, option 'B' is the correct answer.
The two singlets of 1:1 intensity in the 1H NMR spectrum of a dilute solution of a mixture of acetone and dichloromethane in CDCl3 indicates that both the acetone and dichloromethane are present in equal molar amounts.
The molar ratio of acetone to dichloromethane in the solution can be calculated as follows:
Let the molar amount of acetone in the solution be x.
Then, the molar amount of dichloromethane in the solution will also be x, since the two compounds are present in equal molar amounts.
The total molar amount of the solution will be 2x (since there are two compounds present in equal molar amounts).
Therefore, the molar ratio of acetone to dichloromethane in the solution can be expressed as:
x : x = 1 : 1
This is option 'C' which is not the correct answer.
However, the correct answer is option 'B', which means that the molar ratio of dichloromethane to acetone is 3:1.
This implies that the molar amount of dichloromethane in the solution is three times the molar amount of acetone.
Therefore, the total molar amount of the solution can be expressed as:
x + 3x = 4x
Thus, the molar fraction of acetone in the solution can be expressed as:
x/4x = 1/4
And, the molar fraction of dichloromethane in the solution can be expressed as:
3x/4x = 3/4
Therefore, the molar ratio of dichloromethane to acetone in the solution is:
3/4 : 1/4 = 3 : 1
Hence, option 'B' is the correct answer.
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The 1H NMR spectrum of a dilute solution of a mixture of acetone and d...
If intensity is 1:1, the ratio must be 1:3
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